CH3CH₂OH+ NAD CH3CHO + NADH + H¹ The reaction is run in 1.00 mL of 10.0 mM TRIS buffer at pH 8.6. If the pH of the solution falls to 8.4 after 10 minutes, how many mmol of protons were produced by this reaction? (Ka (TRIS) = 8.32 x 10)

CH3CH₂OH+ NAD CH3CHO + NADH + H¹ The reaction is run in 1.00 mL of 10.0 mM TRIS buffer at pH 8.6. If the pH of the solution falls to 8.4 after 10 minutes, how many mmol of protons were produced by this reaction? (Ka (TRIS) = 8.32 x 10)

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter14: Principles Of Neutralization Titrations

Section: Chapter Questions

Problem 14.38QAP

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

Question

Question is in the image, I got 3.07E-8 mmol protons produced. Need to confirm if this is correct.

CH3CH₂OH+ NAD
CH3CHO + NADH + H¹
The reaction is run in 1.00 mL of 10.0 mM TRIS buffer at pH 8.6. If the pH of the solution falls to 8.4
after 10 minutes, how many mmol of protons were produced by this reaction? (Ka (TRIS) = 8.32 x 10).

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