CHALLENGE ACTIVITY 417118.2791720.qx3zqy7 Jump to level 1 3.14.1: String access operations. Given string userString, output "Valid length" if the string's length is greater than or equal to 3. Otherwise, output "Not long enough". End with a newline. Ex: If the input is: garden then the output is: Valid length 1 #include 2 #include 3 using namespace std; 4 5 int main() { 6 7 8 9 10 11} Check string userString; getline(cin, userString); return 0; 1 Next level 2 3 4 >->D-D-

CHALLENGE ACTIVITY 417118.2791720.qx3zqy7 Jump to level 1 3.14.1: String access operations. Given string userString, output "Valid length" if the string's length is greater than or equal to 3. Otherwise, output "Not long enough". End with a newline. Ex: If the input is: garden then the output is: Valid length 1 #include 2 #include 3 using namespace std; 4 5 int main() { 6 7 8 9 10 11} Check string userString; getline(cin, userString); return 0; 1 Next level 2 3 4 >->D-D-

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Code Example 18-21. import tkinter as tk2. from tkinter import ttk3. class TipCalcFrame(ttk.Frame):4. def __init__(self, parent):5. ttk.Frame.__init__(self, parent, padding="20 20 20 20")6. self.pack()7. self.mealCost = tk.StringVar()8. self.tipPercent = tk.StringVar()9. self.tipAmount = tk.StringVar()10. ttk.Label(self, text="Cost of your meal:").grid( column=0, row=0, sticky=tk.E)11. ttk.Entry(self, width=30, textvariable=self.mealCost).grid( column=1, row=0)12. ttk.Label(self, text="Percent to leave as a tip:").grid( column=0, row=1, sticky=tk.E)13. ttk.Entry(self, width=30, textvariable=self.tipPercent).grid( column=1, row=1)14. ttk.Label(self, text="Tip amount:").grid( column=0, row=2, sticky=tk.E)15. ttk.Entry(self, width=30, textvariable=self.tipAmount,…
Please create a class named BST based on the information in the second screenshot. You don't have to modify the class Node. After that, please use the BST class and Node class to create a class BSTApp. Please make sure to use the same class name so that I don't get confused. Also, please make sure to use the following code as a starting point. import java.util.*; public class BSTTest{public static void main(String[] args) {// perform at least one test on each operation of your BST } private int[] randomArray(int size) {// remove the two linesint[] arr = new int[1];return arr;} // the parameters and return are up to you to define; this method needs to be uncommented// private test() {//// }} Base of class Node public class Node {int key;Node left, right, parent; public Node() {} public Node(int num) {key = num;left = null;right = null;parent = null;}} Base of class BST import java.util.*; class BST {// do not change thisprivate Node root;private ArrayList<Integer> data; // DO NOT…
JAVA PROGRAM ASAP Please Modify this program ASAP BECAUSE it does not pass all the test cases when I upload it to hypergrade Please modify so it passes all the test cases because it says 0 out of 2 passed. The program must pass the test case when uploaded to Hypergrade. Thank you import java.util.HashMap;import java.io.BufferedReader;import java.io.FileReader;import java.io.IOException;import java.util.Scanner;public class MorseCodeConverter { private static HashMap<Character, String> morseMap = new HashMap<>(); public static void main(String[] args) { loadMorseCodes(); Scanner scanner = new Scanner(System.in); System.out.println("Please enter a string to convert to Morse code:"); String input = scanner.nextLine().toUpperCase(); String morseCode = convertToMorse(input); System.out.println(morseCode); } private static void loadMorseCodes() { try (BufferedReader reader = new BufferedReader(new…
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How this program would be improved? #include<string.h> #include<stdio.h> #include <fstream> #include<ctype.h> #include<conio.h> #include<iostream> #include<stdlib.h> using namespace std; class Nodo { char Nombre[128]; Nodo * siguiente; public: Nodo(char *N='\0',Nodo * S=NULL) { strcpy(Nombre, N); siguiente=S; } friendclass Lista; }; class Lista { Nodo * inicio; public: Lista() { inicio=NULL; } void Insertar(char*); void Guardar(); void Recuperar(); void Recorrer(); }; void Lista::Insertar(char * N) { Nodo *nuevo=inicio; nuevo=new Nodo(N,inicio); inicio=nuevo; } void Lista::Guardar() { Nodo *aux=inicio; char Nombre_archivo[128]; cout<<endl<<"nombre del archivo a guardar: "; gets(Nombre_archivo); ofstream archivo_salida(Nombre_archivo); if(archivo_salida.fail()){ cout << "Error al abrir el archivo..." << endl; system("pause"); return; } while(aux) { archivo_salida<<aux->Nombre<<endl;…
Implement the copy constructor for the StringVar class using the options given on the right side window. Place the code into the left side using the arrows. NOTE: Be careful! There are decoys! Assume that StringVar.h has the following declaration: #include <iostream> class StringVar {public:StringVar() : max_length(20) { // Default constructor size is 20value = new char[max_length+1];value[0] = '\0';}StringVar(int size); // Takes an int for sizeStringVar(const char cstr[]); // Takes a c-string and copies itStringVar(const StringVar& strObj); // Copy Constructor~StringVar(); // Destructorint size() const { return max_length; } // Access capacityconst char* c_str() const { return value; } // Access valueint length() const { return strlen(value); } // Access lengthStringVar& operator= (const StringVar& rightObj);std::istream& operator>> (std::istream& in, StringVar& strVar);std::ostream& operator<< (std::ostream& out, const StringVar&…
How to fix this code to work... from tkinter import *from tkinter import ttkfrom tkinter import messagebox class Student: def __init__(self, id, fn, ln, dob, m='undefined'): self.id = id self.firstName = fn self.lastName = ln self.dateOfBirth = dob self.major = m list_of_student = []window = Tk()window.geometry("800x750")window.title("Simple Student Management System")list_of_students = []id = 1001 def add_student(): global list_of_students global id if FirstnameEntry.get() =='': messagebox.showerror('erorr', "First name is required") return if LastnameEntry.get() =='': messagebox.showerror('erorr', "Last name is required") return if DateofbirthEntry.get() =='': messagebox.showerror('erorr', "Date of Birth is required") return if MajorEntry.get() =='': instance = Student(id, FirstnameEntry.get(), LastnameEntry.get(), DateofbirthEntry.get()) else: instance = Student(id, FirstnameEntry.get(), LastnameEntry.get(),…
In Java: The CSV (or comma-separated values) format is commonly used for tabular data. Each table row is a line, with columns separated by commas. Items may be enclosed in quotation marks, and they must be if they contain commas or quotation marks. Quotation marks inside quoted fields are doubled. Here is a line with four fields:1729, San Francisco, "Hello, World", "He asked: ""Quo vadis?""" Implement a class CSVReader that reads a CSV file, and provide methodsint numberOfRows()int numberOfFields(int row)String field(int row, int column)
here is the code i have right now i will include screenshots of my output(black background) and my wanted output(white background). in option 1 it asks how many nodes i want to insert into the list i type 4 i want the 4 to be KIM PAM DON TOM but the result of my current output is KIM P it counts each individual string. in C++ please fix thank you. //bt.h - header file contains the object description#include <iostream>//bt.h#define BT_Husing namespace std; class BT{private: struct node { char data; //whatever is the data type; use that node* left; node* right; }; node* root;public: BT(); //Constructor bool isEmpty() const { return root == NULL; } //Check for empty void insert(char); //Insert item in BST void print_preorder(); //Preorder traversing driver void preorderTrav(node*); //Preorder traversing…
Look at the following applet code snippet: 1 import javax.swing.*; 2 import java.awt.*; 3 public class GraphicsTest extends JApplet 4 { 5 public void init() 6 { 7 getContentPane().setBackground(Color.WHITE); 8 } 9 public void paint(Graphics g) 10 { 11 int[] xCoords = {20, 20, 60, 100, 140, 140, 100, 60}; 12 int[] ycoords = {20, 100, 140, 140, 100, 60, 20, 20}; 13 super.paint(g); 14 g.setColor(Color.YELLOW); 15 g.fillPolygon(xCoords, yCoords, 8); 16 g.setColor(color.BLACK); 17 g.setFont(new Font("SansSerif", Font.BOLD, 35)); 18 g.drawString("SLOW", 35, 95); 19 } 20 } How many vertices does the polygon have? Justify your answer.
please fix my code from tkinter import * class TicTacToe:def __init__(self, root, b, states):self.root = Tk()self.b = [[0,0,0],[0,0,0],[0,0,0]]self.states = [[0,0,0],[0,0,0],[0,0,0]]for i in range(3):for j in range(3):self.b[i][j] = Button(font=('Verdana', 56), width=3, bg='yellow',command = lambda r=i,c=j: self.callback(r,c))self.b[i][j].grid(row = i, column = j)self.player = 'X'self.stop_game = Falsemainloop() def check_for_winner(self):for i in range(3):if self.states[i][0]==self.states[i][1]==self.states[i][2]!=0:self.b[i][0].configure(bg='grey')self.b[i][1].configure(bg='grey')self.b[i][2].configure(bg='grey')self.stop_game = True for i in range(3):if self.states[0][i]==self.states[1][i]==self.states[2][i]!=0:self.b[0][i].configure(bg='grey')self.b[1][i].configure(bg='grey')self.b[2][i].configure(bg='grey')self.stop_game = True if…