c. Should you run a comparison test for shift? If your answer is yes, use the Fisher's LSD method at the 5% significance level to determine which shift's production differs. If your answer is no, put zeros in all the cellsof the table below and select "N/A" in all cells of the last column. (Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places. Round your answers2 decimal places.)Population MeanDifferenceDoes the mean score differ at the5% significance level?Confidence Intervalp1- p2u1- u3µ2 - p3d. Should you run a comparison test for emloyee? If your answer is yes, use the Fisher's LSD method at the 5% significance level to determine which employee's production differs. If your answer is no, put zeros inall the cells of the table below and select "N/A" in all cells of the last column. (Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places. Round youranswers to 2 decimal places.)Population MeanDifferenceDoes the mean score differ at theConfidence Interval5% significance level?u1 - p2p1 - p3u1 - 14p1 - p5µ2 - u3u2 - p4µ2 - p5p3 - p4p3 - u5p4 - p5 Chapin Manufacturing Company operates 24 hours a day, five days a week. The workers rotate shifts each week. Management is interested in whether there is a difference in the number of units produced when theemployees work on various shifts. A sample of five workers is selected and their output recorded on each shift and located in the table below (and in the data file link). Assume units produced are normally distributed.Day31Afternoon33Night37SkaffLum202630ClarkTreeceMorgan363438263024132529Click here for the Excel data filea-1. Construct an ANOVA table. (Round intermediate calculations to at least 4 decimal places. Round "SS", "MS", "p-value", and "F" to 4 decimal places.)ANOVASource of VariationSsdfMSFр-valueFactor BFactor AErrorTotala-2. At the 5% significance level, can you conclude that the average number of units produced differ by employee?OYes, since the p-value for employee is less than the significance level.OYes, since the p-value for employee is greater than the significance level.ONo, since the p-value for employee is less than the significance level.ONo, since the p-value for employee is greater than the significance level.b. At the 5% significance level, can you conclude that average units produced differ by shift?OYes, since the p-value for shift is less than the significance level.OYes, since the p-value for shift is greater than the significance level.ONo, since the p-value for shift is less than the significance level.ONo, since the p-value for shift is greater than the significance level.

Question

c. Should you run a comparison test for shift? If your answer is yes, use the Fisher's LSD method at the 5% significance level to determine which shift's production differs. If your answer is no, put zeros in all the cellsof the table below and select &#34;N/A&#34; in all cells of the last column. (Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places. Round your answers2 decimal places.)Population MeanDifferenceDoes the mean score differ at the5% significance level?Confidence Intervalp1- p2u1- u3µ2 - p3d. Should you run a comparison test for emloyee? If your answer is yes, use the Fisher's LSD method at the 5% significance level to determine which employee's production differs. If your answer is no, put zeros inall the cells of the table below and select &#34;N/A&#34; in all cells of the last column. (Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places. Round youranswers to 2 decimal places.)Population MeanDifferenceDoes the mean score differ at theConfidence Interval5% significance level?u1 - p2p1 - p3u1 - 14p1 - p5µ2 - u3u2 - p4µ2 - p5p3 - p4p3 - u5p4 - p5 Chapin Manufacturing Company operates 24 hours a day, five days a week. The workers rotate shifts each week. Management is interested in whether there is a difference in the number of units produced when theemployees work on various shifts. A sample of five workers is selected and their output recorded on each shift and located in the table below (and in the data file link). Assume units produced are normally distributed.Day31Afternoon33Night37SkaffLum202630ClarkTreeceMorgan363438263024132529Click here for the Excel data filea-1. Construct an ANOVA table. (Round intermediate calculations to at least 4 decimal places. Round &#34;SS&#34;, &#34;MS&#34;, &#34;p-value&#34;, and &#34;F&#34; to 4 decimal places.)ANOVASource of VariationSsdfMSFр-valueFactor BFactor AErrorTotala-2. At the 5% significance level, can you conclude that the average number of units produced differ by employee?OYes, since the p-value for employee is less than the significance level.OYes, since the p-value for employee is greater than the significance level.ONo, since the p-value for employee is less than the significance level.ONo, since the p-value for employee is greater than the significance level.b. At the 5% significance level, can you conclude that average units produced differ by shift?OYes, since the p-value for shift is less than the significance level.OYes, since the p-value for shift is greater than the significance level.ONo, since the p-value for shift is less than the significance level.ONo, since the p-value for shift is greater than the significance level.

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