*Chapter 34, Problem 107 A fruit fly of height H sits in front of lens 1 on the central axis through the lens.The lens forms an image of the fly at a distance d = 21 cm from the fly; the image has the fly's orientation and height H = 2.4 H. What are (a) the focal length f, of the lens and (b) the object distance p, of the fly? The fly then leaves lens 1 and sits i forms an image at d = 21 cm that has the same orientation as the fly, but now H = 0.76 H. What are (c) f2 and (d) P2? front of lens 2, which also

*Chapter 34, Problem 107 A fruit fly of height H sits in front of lens 1 on the central axis through the lens.The lens forms an image of the fly at a distance d = 21 cm from the fly; the image has the fly's orientation and height H = 2.4 H. What are (a) the focal length f, of the lens and (b) the object distance p, of the fly? The fly then leaves lens 1 and sits i forms an image at d = 21 cm that has the same orientation as the fly, but now H = 0.76 H. What are (c) f2 and (d) P2? front of lens 2, which also

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter25: Optical Instruments

Section: Chapter Questions

Problem 24P: A jewelers lens of focal length 5.0 cm is used as a magnifier. With the lens held near the eye,...

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An amoeba is 0.305 cm away from the 0.300 cm- focal length objective lens of a microscope. (a) Where is the image formed by the objective lens? (b) What is this image’s magnification? (C) An eyepiece with a 2.00-cm focal length is placed 20.0 cm from the objective. Where is the final image? (d) What angular magnification is produced by the eyepiece? (e) What is the overall magnification? (See Figure 2.39.)
A person sees clearly wearing eyeglasses that have a power of -4.00 diopters when the lenses are 2.00 cm in front of the eyes. (a) What is the focal length of the lens? (b) Is the person nearsighted or farsighted? (c) If the person wants to switch to contact lenses placed directly on the eyes, what lens power should be prescribed?
A microscope has an objective lens with a focal length of 16.22 mm and an eyepiece with a focal length of 9.50 mm. With the length of the barrel set at 29.0 cm, the diameter of a red blood cells image subtends an angle of 1.43 mrad with the eye. It the final image distance is 29.0 cm from the eyepiece, what is the actual diameter of the red blood cell? Hint: To solve this question, go back to basics and use the thin-lens equation.
A microscope has an objective lens with a focal length of 16.22 mm and an eyepiece with a focal length of 9.50 mm. With the length of the barrel set at 29.0 cm, the diameter of a red blood cells image subtends an angle of 1.43 mrad with the eye. It the final image distance is 29.0 cm from the eyepiece, what is the actual diameter of the red blood cell? Hint: To solve this question, go back to basics and use the thin-lens equation.
A converging lens in a vertical plane receives light from an object and forms an inverted image on a screen. An opaque card is then placed next to the lens, covering only the upper half of the lens. What happens to the image on the screen? (a) The upper half of the image disappears. (b) The lower half of the image disappears. (c) 'The entire image disappears, (d) The entire image is still visible, but is dimmer. (e) No change in the image occurs.
An object 1.50 cm high is held 3.00 cm from a person’s cornea, and its reflected image is measured to be 0.16? cm high. (a) What is the magnification? (b) Where is the image? (c) Find the radius of curvature of the convex mirror formed by the cornea. (Note that this technique is used by optometrists to measure the curvature of the cornea for contact lens ?tting. The instrument used is called a keratometer, or curve measurer.)
Suppose you want to use a converging lens to project the image of two trees onto a screen. One tree is a distance x from the lens; the other is at 2%, as in Figure CQ23.7. You adjust the screen so that the near tree is in focus. If you now want the far tree to be in focus, do you move the screen toward or away from the lens? Figure CQ23.7
Andy decides to use an old pair of eyeglasses to make some optical instruments. He knows that the near point in his left eye is 50.0 cm and the near point in his right eve is 100 cm. (a) What is the maximum angular magnification he can produce in a telescope? (b) If he places the lenses 10.0 cm apart, what is the maximum overall magnification he can produce in a microscope? Hint: Go back to basics and use the thin lens equation to solve part (b).
A jewelers lens of focal length 5.0 cm is used as a magnifier. With the lens held near the eye, determine (a) the angular magnification when the object is at the focal point of the lens and (b) the angular magnification when the image formed by the lens is at the near point of the eye (25 cm). (c) What is the object distance giving the maximum magnification?
Suppose a man stands in front of a mirror as shown in Figure 25.50. His eyes are 1.65 m above the floor, and the top of his head is 0.13 m higher. Find the height above the floor of the top and bottom of the smallest mirror in which he can see both the top of his head and his feet. How is this distance related to the man’s height? Figure 25.50 A full-length mirror is one in which you can see all of yourself. It need not be as big as you, and its size is independent of your distance from it.
A leaf of length h is positioned 71.0 cm in front of a converging lens with a focal length of 39.0 cm. An observer views the image of the leaf from a position 1.26 in behind the lens, as shown in Figure P25.25. (a) What is the magnitude of the lateral magnification (the ratio of the image size to the object size) produced by the lens? (b) What angular magnification is achieved by viewing the image of the leaf rather than viewing the loaf directly? Figure P25.25
A particular nearsighted patient cant see objects clearly beyond 15.0 cm from their eye. Determine (a) the lens power required to correct the patients vision and (b) the type of lens required (converging or diverging). Neglect the distance between the eye and the corrective lens.