CI0CH3CH=CHCHCH34-chloro-2-penteneFour stereoisomers exist for 4-chloro-2-pentene. Draw the structure of the isomer that has the E configuration around the double bond and the R configuration atthe chiral center.Use the wedge/hash bond tools to indicate stereochemistry where it exists.• You do not have to explicitly draw H atoms.• If a group is achiral, do not use wedged or hashed bonds on it.Jn (1²

If the two higher priority substituents are on the same side of the double bond, then it is denoted…

CH₂CH=CHCHCH3 4-chloro-2-pentene Four stereoisomers exist for 4-chloro-2-pentene. Draw the structure of the isomer that has the E configuration around the double bond and the R configuration at the chiral center.

CH₂CH=CHCHCH3 4-chloro-2-pentene Four stereoisomers exist for 4-chloro-2-pentene. Draw the structure of the isomer that has the E configuration around the double bond and the R configuration at the chiral center.

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter7: Cycloalkanes

Section: Chapter Questions

Problem 5E

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Concept explainers

Alkanes and Cycloalkanes

Alkanes are saturated organic compounds which are made up of C and H atoms. Alkanes have the general formula of CnH2n+2. Alkane contains sp3 hybridized carbon atoms with four sigmas (σ) bonds & every hydrogen atom is connected with one of the carbon atoms. The size of the alkane could be determined by the number of carbon atoms located in it.

Question

CI
0
CH3CH=CHCHCH3
4-chloro-2-pentene
Four stereoisomers exist for 4-chloro-2-pentene. Draw the structure of the isomer that has the E configuration around the double bond and the R configuration at
the chiral center.
Use the wedge/hash bond tools to indicate stereochemistry where it exists.
• You do not have to explicitly draw H atoms.
• If a group is achiral, do not use wedged or hashed bonds on it.
Jn (1²

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