I am having issues balancing this equation for this chemical formula of a hydrate. Cl3- XH20.12.826 g12.813 g15.667 g15.327 gible,14.533 g14.321 g1.70741.5087L134 1.006g40-016%d39,96lo %x 100]39.916%te(convert eCl3)10234,829y 10?3 le.058y paad (#4 ÷ #3) :1 ib671s compoundarest integer-613.0657 1te determined above, write the general bal-ion PRE-LAB ASSIGNMENT IEXPERIMENT B: MOLAR RATIOS6.Determine the formula for the unkpown hydrate below from the experimental data given.Formula of Hydrate that you used is FeClg xH,0.12.813 gMass of crucible and cover12.826 ga.15.327 gb. Mass of crucible, cover, and hydratec. Mass of hydrate (b-a)d. Mass of anhydrous compound, crucible,and cover after heating15.667 g2.84192514914.533 g14.321 g1.508Mass of anhydrous compound (d – a)f. Mass of water lost (c – e)1.7074L.1342e.SUMMARY OF CALCULATIONS40-016%39.9166 %1. Percent by mass water in hydrate [(f ÷ c) x 100]39.916%2. Average percent by mass water in hydrate3. Moles of anhydrous compound remaining (convert ein grams to moles using molar mass of FeCl3)4. Moles of water lost (convert f in grams tomoles using molar mass of water)5. Molar ratio of water: anhydrous compound (#4 ÷ #3) -blos6. Average molar ratio of water to anhydrous compound4.829y 1023 l6.058y pr:1 1,71-6657:1:17. Average ratio (value in #5) rounded to nearest integer:18. Chemical formula for this hydrate9. Using the chemical formula of the hydrate determined above, write the general bal-anced equation for the dehydration reactionFe = 55.85Cl (35.45)3to bsotanFe Cl3 tH2 OFell) + ClyFe Cla + H20 >

The formula of the hydrate given is FeCl3.1H2O.

Answered: Chemical formula for this hydrate Using…

Chemical formula for this hydrate Using the chemical formula of the hydrate determined above, write the general bal- anced equation for the dehydration reaction Fe - 55.8s

Fundamentals Of Analytical Chemistry

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Chapter7: Statistical Data Treatment And Evaluation

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Chemical Reactions and Equations

When a chemical species is transformed into another chemical species it is said to have undergone a chemical reaction. It consists of breaking existing bonds and forming new bonds by changing the position of electrons. These reactions are best explained using a chemical equation.

Question

100%

I am having issues balancing this equation for this chemical formula of a hydrate.

Cl3- XH20.
12.826 g
12.813 g
15.667 g
15.327 g
ible,
14.533 g
14.321 g
1.7074
1.5087
L134 1.006g
40-016%
d39,96lo %
x 100]
39.916%
te
(convert e
Cl3)
1023
4,829y 10?3 le.058y pa
ad (#4 ÷ #3) :1 ib671
s compound
arest integer
-613
.0657 1
te determined above, write the general bal-
ion

PRE-LAB ASSIGNMENT IEXPERIMENT B: MOLAR RATIOS
6.
Determine the formula for the unkpown hydrate below from the experimental data given.
Formula of Hydrate that you used is FeClg xH,0.
12.813 g
Mass of crucible and cover
12.826 g
a.
15.327 g
b. Mass of crucible, cover, and hydrate
c. Mass of hydrate (b-a)
d. Mass of anhydrous compound, crucible,
and cover after heating
15.667 g
2.8419
25149
14.533 g
14.321 g
1.508
Mass of anhydrous compound (d – a)
f. Mass of water lost (c – e)
1.7074
L.1342
e.
SUMMARY OF CALCULATIONS
40-016%
39.9166 %
1. Percent by mass water in hydrate [(f ÷ c) x 100]
39.916%
2. Average percent by mass water in hydrate
3. Moles of anhydrous compound remaining (convert e
in grams to moles using molar mass of FeCl3)
4. Moles of water lost (convert f in grams to
moles using molar mass of water)
5. Molar ratio of water: anhydrous compound (#4 ÷ #3) -blos
6. Average molar ratio of water to anhydrous compound
4.829y 1023 l6.058y pr
:1 1,71
-6657
:1
:1
7. Average ratio (value in #5) rounded to nearest integer
:1
8. Chemical formula for this hydrate
9. Using the chemical formula of the hydrate determined above, write the general bal-
anced equation for the dehydration reaction
Fe = 55.85
Cl (35.45)3
to bsotan
Fe Cl3 t
H2 O
Fell) + Cly
Fe Cla + H20 >

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