Question 8 01 8 Fill in the blanks: Choices: A - 3H₂O B-6H* Step 1 D - 1 Perform the balancing of the reaction TeO² + N₂O4 →→→ Te + NO³¹ under acidic condition. Choose the letter of the item that should be placed in each of the blank to complete the steps in balancing the given equation. Order matters in answering; answer from left to right, going down. Step 2 Step 3 Step 4 Step 5 Step 6 TeO3²- --> Te N₂04 --> NOS 2H₂0 + 2H₂O + 2H₂0 C-4 2H₂0 + TeO32- --> Te N₂O4 -> 2 NO E-2 Te03²- --> Te + N₂O4 →→ 2NO3 + + N₂04 -> 2NO3 + 4H* Te032- e + e --> Te + N₂04 ->2 NO3 + 4H* + 2 e (2H₂0 + - Te03²- --> Te + + TeO3²- --> Te + N2O4 -> 2NO3 + 4H+ 2 e)
Question 8 01 8 Fill in the blanks: Choices: A - 3H₂O B-6H* Step 1 D - 1 Perform the balancing of the reaction TeO² + N₂O4 →→→ Te + NO³¹ under acidic condition. Choose the letter of the item that should be placed in each of the blank to complete the steps in balancing the given equation. Order matters in answering; answer from left to right, going down. Step 2 Step 3 Step 4 Step 5 Step 6 TeO3²- --> Te N₂04 --> NOS 2H₂0 + 2H₂O + 2H₂0 C-4 2H₂0 + TeO32- --> Te N₂O4 -> 2 NO E-2 Te03²- --> Te + N₂O4 →→ 2NO3 + + N₂04 -> 2NO3 + 4H* Te032- e + e --> Te + N₂04 ->2 NO3 + 4H* + 2 e (2H₂0 + - Te03²- --> Te + + TeO3²- --> Te + N2O4 -> 2NO3 + 4H+ 2 e)
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter17: Electrochemistry
Section: Chapter Questions
Problem 9QAP: Write balanced net ionic equations for the following reactions in acid solution. (a) Liquid...
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Transcribed Image Text:Question 8 01 8
Fill in the blanks:
Choices: A - 3H₂O
B-6H*
Step 1
D - 1
Perform the balancing of the reaction TeO² + N₂O4 →→→ Te + NO³¹ under acidic condition. Choose the letter of the item that should be placed in each of the blank to complete the steps in balancing the given equation. Order matters
in answering; answer from left to right, going down.
Step 2
Step 3
Step 4
Step 5
Step 6
TeO3²- --> Te
N₂04 --> NOS
2H₂0 +
2H₂O +
2H₂0
C-4
2H₂0
+
TeO32- --> Te
N₂O4 -> 2 NO
E-2
Te03²- --> Te +
N₂O4 →→ 2NO3
+
+ N₂04 -> 2NO3 + 4H*
Te032-
e +
e
--> Te +
N₂04 ->2 NO3 + 4H* + 2 e
(2H₂0 +
- Te03²- --> Te +
+ TeO3²-
--> Te +
N2O4 -> 2NO3 + 4H+ 2 e)
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