The steam reforming reaction of methane follows this chemical equation: CH4(g) + H₂O(g) → CO(g) + 3 H₂(g) AH° = +193 kJ/mol At 298 K the reaction lies far to the reactant side with a very small equilibrium constant of 2.35 x 10-23. To obtain a significant amount of the desired hydrogen gas product, the reaction is operated at very high temperatures. What is the equilibrium constant at 1100 K? (Note: Some of these numbers have been changed from their actual values for the purpose of the exam.) Unitless. Do not use scientific notation. Just give the answer as a number with no decimal places)

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Your Question:
The steam reforming reaction of methane follows this chemical equation:
CH4(g) + H₂O(g) → CO(g) + 3 H₂(g) AH° = +193 kJ/mol
At 298 K the reaction lies far to the reactant side with a very small equilibrium
constant of 2.35 x 10-23. To obtain a significant amount of the desired hydrogen gas
product, the reaction is operated at very high temperatures. What is the equilibrium
constant at 1100 K?
(Note: Some of these numbers have been changed from their actual values for the
purpose of the exam.)
Unitless. Do not use scientific notation. Just give the answer as a number with no
decimal places)
Transcribed Image Text:The steam reforming reaction of methane follows this chemical equation: CH4(g) + H₂O(g) → CO(g) + 3 H₂(g) AH° = +193 kJ/mol At 298 K the reaction lies far to the reactant side with a very small equilibrium constant of 2.35 x 10-23. To obtain a significant amount of the desired hydrogen gas product, the reaction is operated at very high temperatures. What is the equilibrium constant at 1100 K? (Note: Some of these numbers have been changed from their actual values for the purpose of the exam.) Unitless. Do not use scientific notation. Just give the answer as a number with no decimal places)
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