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- Which of the following is a spontaneous reaction.? a. Rxn with ΔH =- 10Kj/mol ΔS= -5J/mol T= 300K b. NaCl +H20 -> NaOH + HCl 25C c. H20(l) -> H2O(s) Temp: 25C d. Dissolution of 100g of solid sugar in 100 mL ice tea. Consider following reaction: HgO (s) -> Hg(l) + ½ O2 (g) Delta H = +90.7 kj/mol. What quantity of heat in kj/mol is required to produce one mole HgO? Write your answer without units. Given the following data 2ClF(g) + O2(g) --> Cl2O(g) + F2O (g) Delta H= 167.4 kJ I 2ClF3(g) + 2O2(g) --> Cl2O(g) + 3F2 O (g) Delta H= 341.4 kJ II 2 F2(g) + O2(g) ---> 2F2O (g) Delta H= -43.4 kJ III Calculate the delta H in kJ for below reaction: ClF(g) + F2(g) ---> ClF3(g)Elaborat ur answer pls thank uDétermine s'il y aura un précipité former quand on mélange 50 ml de CaCl2 0,2 M et 100 ml de Na2SO4 0,04 M? (Kps CaSO4=1,95 x 10-4)
- Hexanoic acid was added to an immiscible biphasic solvent sysem, water and CCl4 at 20.0OC and the equilibrium concentrations of hexanoic acid were determined to be 3.66 g/L in H2O and 67.0 g/L in CCl4. Caluclate the distrubution coeffiecent (D1) of hexanoic acid in CCl4 with respect to water.The acid-base indicator HIn undergoes the following reaction in dilute aqueous solution: HIncolor1H++Incolor2 The following absorbance data were obtained for a 5.00 I0-4 M solution of HIn in 0.1 M NaOH and 0.1 M HC1. Measurements were made at wavelengths of 485 nm and 625 nm with 1.00-cm cells. 0.1 M NaOH A485 = 0.075 A625 = 0.904 0.1 M HC1 A485 = 0.487 A625 = 0.181 In the NaOH solution, essentially all of the indicator is present as In-; in the acidic solution, it is essentially all in the form of HIn. (a) Calculate molar absorptivities for In- and HIn at 485 and 625 nm. (b) Calculate the acid dissociation constant for the indicator ¡fa pH 5.00 buffer containing a small amount of the indicator exhibits an absorbance of 0.567 at 485 nm and 0.395 at 625 nm (1.00-cm cells). (c) What is the pH of a solution containing a small amount of the indicator that exhibits an absorbance of0.492 at 485 nm and 0.245 at 635 nm (1.00-cm cells)? (d) A 25.00-mL aliquot of a solution of purified weak organic acid HX required exactly 24.20 mL of a standard solution of a strong base to reach a phenolphthalein end point. When exactly 12.10 mL of the base was added to a second 25.00-mL aliquot of the acid, which contained a small amount of the Indicator under consideration, the absorbance was found to be 0.333 at 485 nm and 0.655 at 625 nm (1.00-cmcells). Calculate the pH of the solution and Ka for the weak acid. (e) What would be the absorbance of a solution at 485 and 625 nm (1.50-cm cells) that was 2.00 10-4 M in the indicator and was buffered to a pH of 6.000?(9.29 × 105/8)-20.81 = with correct sig figs
- What is ΔHsys for a reaction at 16.9 °C with ΔSsurr = -159 J mol-1 K-1 ? Express your answer in kJ mol-1 to at least two significant figures. (Please type answer no write by hend)DESCRIBE THE PROCEDURE OF d) 600 mL of 3.00% (w/v) aqueous BaCl2from a 0.400 M BaCl2solution. (e) 2.00 L of 0.120 M HClO4from the commercial reagent [71.0% HClO4(w/w), specificgravity1.67]. (f) 9.00 L of a solution that is 60.0 ppm in Na+, starting with solid Na2SO4Potansiyometride, aşağıdakilerden hangisi standart elektrottur? A. Kalsiyum elektrodu B. hidrojen elektrodu C. bakır elektrodu D. potasyum elektrodu Permanganat iyonunun mangan(II) iyonuna dönüştüğü titrasyonun dönüm noktası tayininde A. Kırmızı veya mavi turnosol kağıdı kullanılır B. pH probu kullanılır C. metil oranj belirteci eklenir D. permanganat iyonunun pembe kaybolur …………………………………….. gives the relative response of an ion-selective electrode to different species with the same charge.A. Transition coefficientB. ion coefficientC. counterion coefficientD. selectivity coefficient
- Pls help me with the following and make sure its 100% its important asap, thank you smGiven the SEPs: Br2(l) + 2e- ↔ 2Br- E0 = 1.078 V Br2(aq) + 2e- ↔ 2Br- E0 = 1.098 V a. Calculate the Keq for the reaction: Br2(l) ↔ Br2(aq) b. Calculate the solubility of Br2 (159.808) in water at 250C. Express in g/L.El poder de rotación específico de la sacarosa a 20 °C es [alfa]D20 = +66,53 grados/(dm g mL-1). ¿Cuál es su poder de rotación molar, expresado en grados/(dm mol L-1)? (Peso molecular de la sacarosa: 342,3). 1). 5.14 2). 22.77 3). 194.4 4). 22773