H2(g) + Cl2(g) ----> 2 HCl(g) (OR H2(g) + Cl2(g) right arrow 2 HCl(g) Use the following conversions: 1 mol = MW in g (2 d.p.) = 22.414 L What is the percent yield of HCI if 50.00 g of H2 (MW = 2.02 12 ads to formation of 231 g of HCI (MW= Theoretical yield = (Express with unit and compound, for example 'g Zn'). Percent yield = (Express as '%'). x (1805 g HCI, 1800 g HCI, 1805.0 g HCI, 1804.95 g HCI, 1810 g HCI) Theoretical Yield x (12.8 %, 12.8%, 12.80 %, 12.798 %, 13 %, 13%, 12.80%, 12.798%, 13.%, 13. %) Percent Yield

Chemistry: Principles and Reactions
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Chapter8: Thermochemistry
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Problem 63QAP: Butane gas, C4H10, is sold to campers as bottled fuel. Its density at 25C and 1.00 atm is 2.38 g/L....
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H2(g) + Cl2(g) ----> 2 HCl(g)
(OR H2(g) + Cl2(g) right arrow 2 HCl(g)
Use the following conversions: 1 mol = MW in g (2 d.p.) = 22.414 L
What is the percent yield of HCI if 50.00 g of H2 (MW = 2.02 12 ads to formation of 231 g of HCI (MW=
Theoretical yield =
(Express with unit and compound, for example 'g Zn').
Percent yield =
(Express as '%').
x (1805 g HCI, 1800 g HCI, 1805.0 g HCI, 1804.95 g HCI, 1810 g HCI) Theoretical Yield
x (12.8 %, 12.8%, 12.80 %, 12.798 %, 13 %, 13%, 12.80%, 12.798%, 13.%, 13. %) Percent Yield
Transcribed Image Text:H2(g) + Cl2(g) ----> 2 HCl(g) (OR H2(g) + Cl2(g) right arrow 2 HCl(g) Use the following conversions: 1 mol = MW in g (2 d.p.) = 22.414 L What is the percent yield of HCI if 50.00 g of H2 (MW = 2.02 12 ads to formation of 231 g of HCI (MW= Theoretical yield = (Express with unit and compound, for example 'g Zn'). Percent yield = (Express as '%'). x (1805 g HCI, 1800 g HCI, 1805.0 g HCI, 1804.95 g HCI, 1810 g HCI) Theoretical Yield x (12.8 %, 12.8%, 12.80 %, 12.798 %, 13 %, 13%, 12.80%, 12.798%, 13.%, 13. %) Percent Yield
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