Hydrogen gas (MW = 2.02 g/mol) can be produced from the reaction of methane (MW = 16.05 g/mol) and water vapor (MW = 18.02 g/mol) according to the following reaction equation (called methane reforming):  CH4(g) + H2O(g) --> CO(g) + 3 H2(g)    If 262 g of CH4 reacts with excess H2O at 423 K and 0.862 atm, what volume of H2 gas will form?

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Chapter4: Stoichiometry
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Hydrogen gas (MW = 2.02 g/mol) can be produced from the reaction of methane (MW = 16.05 g/mol) and water vapor (MW = 18.02 g/mol) according to the following reaction equation (called methane reforming): 

CH4(g) + H2O(g) --> CO(g) + 3 H2(g)

 

 If 262 g of CH4 reacts with excess H2O at 423 K and 0.862 atm, what volume of H2 gas will form? 

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