chloride was passed into potassium iodide solution where it liberated iodine: Cl2 + KI → KCl + I2 The iodine liberated was estimated by adding sodium thiosulfate, the reaction being I2 + Na2S2O3 → NaI + Na2S4O6 If 5.6 g of crystallized sodium thiosulfate, Na2S2O3 5H2O ,were used up, how many grams of manganese were present? MW (g/mole): I =126.9; Mn =54.94; Cl = 35.45; K = 39.09; Na = 23; S = 32

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