Choose the appropriate portion to complete the algorithm written to find this summation x2 x+ x6 x8 X" S = 1- + 11! + ................ 2! 5! 8! n! 1- Start 2- Read X, N 3- S=1, I=0 4-1-I+1 4-1-I+1 5- F=1,J-0 5- F-1,J-0 6- J-J+1 6- J-J+1 7-F-F*J 7-F=F*J 8- IfJ< (3*1-1) go to 6 8- If J< (3*I-1) go to 6 9-S-S+(-1) + xa 9-S=S+(-1)! * 10- If I

Computer Networking: A Top-Down Approach (7th Edition)
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ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
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Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
Choose the appropriate portion to complete the algorithm written to find this
summation
x+ x6
+
2!
x2
X8
S = 1-
...................
5!
8!
11!
n!
1- Start
2- Read X, N
3- S=1, I=0
4-I=I+1
4-1=I+1
5- F=1,J=0
5- F=1,J=0
6- J=J+1
6- J-J+1
7-F-F*J
7-F=F*J
8- If J< (3*1-1) go to 6
8- If J< (3*I-1) go to 6
9- S-S+(-1)! *:
9-S =S+(-1)' *
10- If I<N go to 4
11- Print S
10- If I< N go to 4
12- End
11- End
The answer is
the answer Is
4-I=I+1
4-1=I+1
5- F=0, J=0
5- F=1, J=0
6- J-J+1
6- J=J+1
7-F=F*J
7-F=F*J
8- If J< (3*I-1) go to 6
8- If J< (3*I-1) go to 6
9- S=s+(-1) +"
9-S-s+(-1)-1 + x21
10- If I<N go to 4
10- If I<N go to 4
11- Print S
11- Print S
12- End
12- End
the answer is
the Answer is
Transcribed Image Text:Choose the appropriate portion to complete the algorithm written to find this summation x+ x6 + 2! x2 X8 S = 1- ................... 5! 8! 11! n! 1- Start 2- Read X, N 3- S=1, I=0 4-I=I+1 4-1=I+1 5- F=1,J=0 5- F=1,J=0 6- J=J+1 6- J-J+1 7-F-F*J 7-F=F*J 8- If J< (3*1-1) go to 6 8- If J< (3*I-1) go to 6 9- S-S+(-1)! *: 9-S =S+(-1)' * 10- If I<N go to 4 11- Print S 10- If I< N go to 4 12- End 11- End The answer is the answer Is 4-I=I+1 4-1=I+1 5- F=0, J=0 5- F=1, J=0 6- J-J+1 6- J=J+1 7-F=F*J 7-F=F*J 8- If J< (3*I-1) go to 6 8- If J< (3*I-1) go to 6 9- S=s+(-1) +" 9-S-s+(-1)-1 + x21 10- If I<N go to 4 10- If I<N go to 4 11- Print S 11- Print S 12- End 12- End the answer is the Answer is
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