:puolution:Given:You want to change 5kg of ice at 0 °Cinto water at 55°C.Lf for water = 80 cal/gmkcal/kgx°C)c = (1.00%3DFind:The amount of heat needed in calories.Solution:Page 3 of 4

Given data: Mass (m) = 5 kg = 5000 g Initial temperature (T0) = 0°C Final temperature (T) = 55°C…

Answered: Civen: into water at 55°C. Lf for…

Civen: into water at 55°C. Lf for water= 80 cal/gm kcal/kgx°C) You want to change 5kg of ice at 0 °C c = (1.00 %3D The amount of heat needed in calories.

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter1: Temperature And Heat

Section: Chapter Questions

Problem 93P: A man consumes 3000 kcal of food in one day, converting most of it to thermal energy to maintain...

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Question

:pu
olution:
Given:
You want to change 5kg of ice at 0 °C
into water at 55°C.
Lf for water = 80 cal/gm
kcal/kgx°C)
c = (1.00
%3D
Find:
The amount of heat needed in calories.
Solution:
Page 3 of 4

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