Classify the equilibrium solutions as asymptotically stable or unstable. dy = y(y – 4)(y – 7), yo 2 0 dt O y(t) = 0 is asymptotically stable, y(t) = 4 is unstable, y(t) = 7 is asymptotically stable. y(t) = 0 is asymptotically stable, y(1) = 4 is asymptotically stable, y(1) = 7 is unstable. y(t) = 0 is unstable, y(t) = 4 is asymptotically stable, y(t) = 7 is asymptotically stable. y(t) = 0 is unstable, y(t) = 4 is asymptotically stable, y(t) = 7 is unstable. O y(t) = 0 is unstable, y(t) = 4 is unstable, y(t) = 7 is unstable.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Classify the equilibrium solutions as asymptotically stable or unstable.
dy
= y(y – 4)(y – 7), yo > 0
dt
O y(t) = 0 is asymptotically stable, y(t) = 4 is unstable, y(t) = 7 is asymptotically stable.
O y(1) = 0 is asymptotically stable, y(1) = 4 is asymptotically stable, y(1) = 7 is unstable.
O y(t) = 0 is unstable, y(t) = 4 is asymptotically stable, y(t) = 7 is asymptotically stable.
O y(t) = 0 is unstable, y(t) = 4 is asymptotically stable, y(t) = 7 is unstable.
O y(t) = 0 is unstable, y(t) = 4 is unstable, y(t) = 7 is unstable.
Transcribed Image Text:Classify the equilibrium solutions as asymptotically stable or unstable. dy = y(y – 4)(y – 7), yo > 0 dt O y(t) = 0 is asymptotically stable, y(t) = 4 is unstable, y(t) = 7 is asymptotically stable. O y(1) = 0 is asymptotically stable, y(1) = 4 is asymptotically stable, y(1) = 7 is unstable. O y(t) = 0 is unstable, y(t) = 4 is asymptotically stable, y(t) = 7 is asymptotically stable. O y(t) = 0 is unstable, y(t) = 4 is asymptotically stable, y(t) = 7 is unstable. O y(t) = 0 is unstable, y(t) = 4 is unstable, y(t) = 7 is unstable.
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