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cm (see figure below). The larger loop, which initially carries a current I = 8.8 A, is cut and its current is reduced to zero over a time interval of 9.0 10-7 s. Find the average current in the smaller loop during this time interval. (The magnetic field of th

cm (see figure below). The larger loop, which initially carries a current I = 8.8 A, is cut and its current is reduced to zero over a time interval of 9.0 10-7 s. Find the average current in the smaller loop during this time interval. (The magnetic field of th

College Physics
College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter1: Introduction: The Nature Of Science And Physics
Section: Chapter Questions
Problem 22PE: What is the area of a circle 3.102 cm in diameter?
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A small circular loop of wire of radius 5.0 cm and resistance R = 1.5 10-3 ohms is centered inside a large circular loop of wire of radius 50 cm (see figure below). The larger loop, which initially carries a current I = 8.8 A, is cut and its current is reduced to zero over a time interval of 9.0 10-7 s. Find the average current in the smaller loop during this time interval. (The magnetic field of the larger loop is approximately constant over the smaller loop.)

magnitude   
direction(clockwise)or(counterclockwise)
50 ст 10 cm
Transcribed Image Text:50 ст 10 cm
Expert Solution
Step 1

We know that the formula of the magnetic field is 

B = μ0I2r

where I is a current 

r is the radius of the coil

We also know that the area of the loop is given as 

A = πr2A= π×5×10-22A= 7.85××10-3  m2

here A is the Area 

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