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Collision 2 (M₁ >> M₂) 4 extra masses on M₁ M₁ M₂ 401.27 = 191.6 g = Mass 0.40127 kg 0.1916 kg Initial Time 0.0942 s 0 Initial Velocity 1.0616 m/s 0 m/s Final Time 0.4371 s 0.1339 s Final Velocity 0.2288 m/s 0.7468 m/s Initial Momentum Final M1 = 0.4260 m1 = 0.092 Momentum

Collision 2 (M₁ >> M₂) 4 extra masses on M₁ M₁ M₂ 401.27 = 191.6 g = Mass 0.40127 kg 0.1916 kg Initial Time 0.0942 s 0 Initial Velocity 1.0616 m/s 0 m/s Final Time 0.4371 s 0.1339 s Final Velocity 0.2288 m/s 0.7468 m/s Initial Momentum Final M1 = 0.4260 m1 = 0.092 Momentum

Principles of Physics: A Calculus-Based Text
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter8: Momentum And Collisions
Section: Chapter Questions
Problem 8OQ: The kinetic energy of an object is increased by a factor of 4. By what factor is the magnitude of...
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University Physics 1 - Conservation of Momentum

I need help with this problem and an explanation of the solutions described below:

 

Pick one of the collisions (identify which one it is) from the air track collision experiment.

Collision 2 ( described in the image below) 

and calculate the mechanical energy both before and after the collision. Was energy lost or gained? If it was lost, where did it go? If it was gained, where did it come from?

Collision 2 (M₁ >> M₂) 4 extra masses on M₁ M₁ M₂ 401.27 = 191.6 g = Mass 0.40127 kg 0.1916 kg Initial Time 0.0942 s 0 Initial Velocity 1.0616 m/s 0 m/s Final Time 0.4371 s 0.1339 s Final Velocity 0.2288 m/s 0.7468 m/s Initial Momentum Final M1 = 0.4260 m1 = 0.092 Momentum
Transcribed Image Text:Collision 2 (M₁ >> M₂) 4 extra masses on M₁ M₁ M₂ 401.27 = 191.6 g = Mass 0.40127 kg 0.1916 kg Initial Time 0.0942 s 0 Initial Velocity 1.0616 m/s 0 m/s Final Time 0.4371 s 0.1339 s Final Velocity 0.2288 m/s 0.7468 m/s Initial Momentum Final M1 = 0.4260 m1 = 0.092 Momentum
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