common-emitter

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Solve for H-K pls ty in advance

USE APPROXIMATE ANALYSIS
USE 2 decimal places, no commas.
Given:
Single-stage, voltage-divider biased, common-emitter with
1. VCC = 20V
2. R1 = 48kohms
%3!
3. R2 = 10kohms
4. RC = 3kohms
5. RE = 1kohms
6. RS = 11ohms
7. RL = 1kohms
8. BDC = BAC = 125
9, **
10.C, andC, are coupling capacitors.
11.Cz is bypass capacitor
12.
13.Solve for:
a. VB = 3.28 V ;
b. VE = 2.58 V ;
c. IE = 2.58 mA;
d. VCE = 9.73 V;
e. VC = 12.31 V;
f. re' = 10 ohms ;
g. Rin(base) = 1.10 kohms ;
h. Rin(tot) = Blank 8 kohms ;
i. Voltage gain (Av) = Blank 9;
j. Attenuation (Att) = Blank 10;
k. Overall voltage gain (AVT) = Blank 11;
Transcribed Image Text:USE APPROXIMATE ANALYSIS USE 2 decimal places, no commas. Given: Single-stage, voltage-divider biased, common-emitter with 1. VCC = 20V 2. R1 = 48kohms %3! 3. R2 = 10kohms 4. RC = 3kohms 5. RE = 1kohms 6. RS = 11ohms 7. RL = 1kohms 8. BDC = BAC = 125 9, ** 10.C, andC, are coupling capacitors. 11.Cz is bypass capacitor 12. 13.Solve for: a. VB = 3.28 V ; b. VE = 2.58 V ; c. IE = 2.58 mA; d. VCE = 9.73 V; e. VC = 12.31 V; f. re' = 10 ohms ; g. Rin(base) = 1.10 kohms ; h. Rin(tot) = Blank 8 kohms ; i. Voltage gain (Av) = Blank 9; j. Attenuation (Att) = Blank 10; k. Overall voltage gain (AVT) = Blank 11;
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