Compare the alternatives C and D on the basis of a present worth analysis using an interest rate of 10% per year and a study period of 10 years. Alternative First Cost $-40,000 $-25,000 AOC, per Year Annual Increase in Operating Cost, per Year Salvage Value Life, Years $-9,000 $-10,000 $-200 $-600 $11,000 $200 10 5 The present worth of alternative C is $ -33518.05 and that of alternative D is $-102608.3 Alternative D voffers the lower present worth.
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- You have been asked to evaluate two alternatives, X and Y, that may increase plant capacity for manufacturing high-pressure hydraulic hoses. The parameters associated with each alternative have been estimated. Which one should be selected on the basis of a present worth comparison at an interest rate of 12% per year? Why is yours the correct choice? Alternative X Y First cost, $ −45,000 −58,000 Maintenance cost, $/year −8,000 −4,000 Salvage value, $ 2,000 12,000 Life, years 5 5A company that makes food-friendly silicone (for use in cooking and baking pan coatings) is considering the independent projects shown, all of which can be considered to be viable for only 10 years. If the company’s MARR is 15% per year, determine which should be selected on the basis of a present worth analysis. Financial values are in $1000 units. A B C D First cost, $ −1,200 −2,000 −5,000 −7,000 Annual net income, $/year 200 400 1100 1300 Salvage value, $ 5 6 8 7Compare two alternatives for a physical security system surrounding a power distribution substation using annual worth analysis and a MARR of 10% per year. System Condi Torro First cost, $ −25,000 −130,000 M&O cost, $ per year −9,000 −2,500 Salvage value, $ 3,000 100,000 Life, years 3 ∞
- Using the cash flow shown below decide which alternative is the most economical using (a) Annual Worth analysis and (b) Present worth analysis. What should be the first cost of the two other alternatives to breakeven with the selected alternative using (c) Present Worth analysis and (d) Annual Worth Analysis. MARR is 10% A B C First Cost, Php -90,000 -400,000 -650,000 Annual Cost. Php/year -40,000 -20,000 -13,000 Overhaul every 10 years, Php -- -- -80,000 Salvage Value, Php 7,000 25,000 200,000 Life, years 3 10 INFINITYYou have been asked to evaluate two alternatives, X and Y, that may increase plant capacity for manufacturing high-pressure hydraulic hoses. The parameters associated with each alternative have been estimated. Which one should be selected on the basis of a present worth comparison at an interest rate of 11% per year? Why is yours the correct choice? Alternative X Y First Cost $-30,000 $-60,000 Maintenance cost, per year $-9000 $-3000 Salvage Value $1,500 $2,500 Life 5 years 5 years The present worth of alternative X is $ __ and that of alternative Y is$ __. Alternative __ is selected by the company.Dexcon Technologies, Inc. is evaluating two alternatives to produce its new plastic filament with tribological (i.e., low friction) properties for creating custom bearings for 3-D printers. The estimates associated with each alternative are shown below. Using a MARR of 20% per year, which alternative has the lower present worth? Method DDM LS First cost, $ −164,000 −370,000 M&O cost, $/year −55,000 −21,000 Salvage value, $ 0 30,000 Life, years 2 4
- You have been asked to evaluate two alternatives, X and Y, that may increase plant capacity for manufacturing high-pressure hydraulic hoses. The parameters associated with each alternative have been estimated. Which one should be selected on the basis of a present worth comparison at an interest rate of 15% per year? Why is yours the correct choice? Alternative X Y First Cost $-25,000 $-80,000 Maintenance cost, per Year $-13000 $-7000 Salvage Value $3,500 $4,500 Life 5 years 5 years The present wortIt is proposed to place a cable on existing pole line along the shore of a lake to connect two points on opposite sides. Which is more economical?Compare alternatives using the following methods:a) ROR on Additional Investment Methodb) Annual Cost Methodc) Equivalent Uniform Annual Cost Methodd) Present Worth Cost MethodA new alloy can be produced by Process A, which costs $200,000 to implement. The operating cost will be $10,000 per quarter with a salvage value of $25,000 after its 2-year life. Process B will have a first cost of $250,000, an operating cost of $15,000 per quarter, and a $40,000 salvage value after its 4-year life. The interest rate is 8% per year compounded quarterly. Using present value analysis which process should be selected.
- The Briggs and Stratton Commercial Division designs and manufacturers small engines for golf turf maintenance equipment. A robotics-based testing system with support equipment will ensure that their new signature guarantee program entitled "Always Insta-Start" does indeed work for every engine produced. Pull System Push System First cost of equipment $-1,300,000 $-2,400,000 AOC per Year $-720,000 $-520,000 Salvage Value $110,000 $100,000 Estimated Life 8 years 8 years Compare the annual worth of the two systems at MARR = 14% per year. Select the better system. The (Click to select) pull system push system is determined to be the better system.There are 5 national projects with infinite life time listed below. Select the best two projects if MARR is 8% per year using rate of return analysis? Project First Cost A 2000 B 1000 C 1500 D 7000 E 5000 ORDER: Annual income 200 130 150 600 260 Calculate i* for each alternativeAn engineer launches a project in the country's top technohub. This involves rental of a computer unit for online class students. He felt that because of the density of students in the area, 90% of his 30-units will be occupied per sem (5 months each) per year. He desires a rate of return of 20%. Other pertinent data are the following: Assess the project using (1) ROR, (2) Present Worth Method, and (3) Future Worth Method. (4) Estimate the payback period of this project. Help me solve this manually.