Compare the following three alternatives by the IRR method, given MARR of 6%%/year. First find if they are feasible nd then compare them with the incremental rate of retum method (AROR). Alt. Construction cost S Benefits S/yr Salvage S Service Life (yrs) 510,000 145,000 -10,000 775,000 155,000 15,000 1,075,000 165,000 20,000
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- Two machines can be used to produce a part from titanium. The costs and other cash flows associated with each alternative are estimated. The salvage values are constant regardless of when the machines are replaced. Determine which alternative(s) should be selected for further analysis if alternatives must have a payback of 5 years or less. Perform the analysis with (a) i = 0%, and (b) i = 10% per year. Machine Semiautomatic Automatic First cost, $ −40,000 −90,000 Net annual income, $ per year 10,000 15,000 Maximum life, years 10 10 Salvage value, $ 0 0Compare three alternatives on the basis of their capitalized costs at i = 10% per year. Alternative E F G First cost, $ −50,000 −300,000 −900,000 AOC, $ per year −30,000 −10,000 −3,000 Salvage value, $ 5,000 70,000 200,000 Life, years 2 4 ∞Compare two alternatives for a physical security system surrounding a power distribution substation using annual worth analysis and a MARR of 10% per year. System Condi Torro First cost, $ −25,000 −130,000 M&O cost, $ per year −9,000 −2,500 Salvage value, $ 3,000 100,000 Life, years 3 ∞
- You have been asked to evaluate two alternatives, X and Y, that may increase plant capacity for manufacturing high-pressure hydraulic hoses. The parameters associated with each alternative have been estimated. Which one should be selected on the basis of a present worth comparison at an interest rate of 11% per year? Why is yours the correct choice? Alternative X Y First Cost $-30,000 $-60,000 Maintenance cost, per year $-9000 $-3000 Salvage Value $1,500 $2,500 Life 5 years 5 years The present worth of alternative X is $ __ and that of alternative Y is$ __. Alternative __ is selected by the company.You have been asked to evaluate two alternatives, X and Y, that may increase plant capacity for manufacturing high-pressure hydraulic hoses. The parameters associated with each alternative have been estimated. Which one should be selected on the basis of a present worth comparison at an interest rate of 15% per year? Why is yours the correct choice? Alternative X Y First Cost $-25,000 $-80,000 Maintenance cost, per Year $-13000 $-7000 Salvage Value $3,500 $4,500 Life 5 years 5 years The present wortMachines that have the following costs are under consideration for a robotized welding process. Use an interest rate of 10% per year and PW analysis to determine which machine should be selected. Machine X Machine Y First cost, $ −250,000 −430,000 AOC, $ per year −60,000 −40,000 Salvage value, $ 70,000 95,000 Life, years 3 6
- 1. Two methods can be used for producing expansion anchors. Method A costs $70,000 initially and will have a $15,000 salvage value after 3 years. The operating cost with this method will be $30,000 per year. Method B will have a first cost of $135,000, an operating cost of $8,000 per year, and a $40,000 salvage value after its 3-year life. At the MARR of 12% per year, which method should be used on the basis of a present worth analysis?You have been asked to evaluate two alternatives, X and Y, that may increase plant capacity for manufacturing high-pressure hydraulic hoses. The parameters associated with each alternative have been estimated. Which one should be selected on the basis of a present worth comparison at an interest rate of 12% per year? Why is yours the correct choice? Alternative X Y First cost, $ −45,000 −58,000 Maintenance cost, $/year −8,000 −4,000 Salvage value, $ 2,000 12,000 Life, years 5 5Solve all this question......you will not solve all questions then I will give you down?? upvote.... Jenny is an engineer for a municipal power plant. The plant uses natural gas, which is currently provided from an existing pipeline at an annual cost of $10000 per year. Jenny is considering a project to construct a new pipeline. The initial cost of the new pipeline would be $35000, but it would reduce the annual cost to $5000 per year. Assume an analysis period of 20 years and no salvage value for either the new or existing pipeline. The interest rate is 6%. Show work a) Determine the equivalent uniform annual cost (EUAC) for the new pipeline. b) Should the new pipeline be built?
- A company that makes food-friendly silicone (for use in cooking and baking pan coatings) is considering the independent projects shown, all of which can be considered to be viable for only 10 years. If the company’s MARR is 15% per year, determine which should be selected on the basis of a present worth analysis. Financial values are in $1000 units. A B C D First cost, $ −1,200 −2,000 −5,000 −7,000 Annual net income, $/year 200 400 1100 1300 Salvage value, $ 5 6 8 7A newly proposed project has a first cost of $ 211962 and estimated annual income of $46410 per year for 10 years. Determine the PW value if the MARR is 10.4% per year.2. Two methods can be used for injection molding insulin injection pens. Method A Molding costs $120,000 initially and will have a $30,000 salvage value after 5 years. The operating cost with this method will be $20,000 per year. Method B Molding will have a first cost of $150,000, an operating cost of $15,000 per year, and a $40,000 salvage value after its 6 - year life. Determine which method should be selected at a MARR of 10%. - Use Present Worth Analysis Solve in Excel