Compare the machines shown below on the basis of their capitalized cost. Use I =10% per year. Machine A Machine B First cost,$ 20.000 300,000 Annual cost,S/year 9000 7000 Salvage value.S 4000 Life, yrs 3
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- there are three machines in the mechanicle angineering lab A ,B , and C and need to be evaluted economically, machine A has first cost of $4500,an annual operating cost(AOE) of $900, a salvage value of $200 and a service life 4 year. machine B has first cost of $3500, an annual operating cost(AOE) of $700, a salvage value of $350, and a service life 4 year. machine C has first cost of $6000, an annual operating cost(AOE) of $50, a salvage value of $100 and a service life 8 year. which machine should be selected ? the MARR is 10% per year. (a) machine A (B) machine B (c) machine C (d) noneTwo lathes are being considered in the manufacture of certain machine parts. Data is given below, all cost in peso: LATHE A LATHE B First Cost 40,000 56,000 Salvage Value 5,000 7,000 Annual Maintenance 2,000 2,800 Operation, Cost/hour 4 3.5 Life, in years 10 12 Time per part (hours) 0.40 0.25 REQUIRED: Determine the number of machine parts/year that could be produced so that 2 lathes will be equally economical if the MARR is 18%. Use AWM If the number of parts is 10,000 units, which lathe will you recommend? Use ROR If the number of parts is 10,000 units, which lathe will you recommend? Use PWM If the number of parts is 10,000 units, which lathe will you recommend? Use EUACQ. Find the capitalized cost at 15% interest, initial cost $200000, Annual operating cost $40000.
- Alternate x has first cost of$20000 an operating cost of$9000 per year and $5000salvage value after 8 year .alternate Y will cost $12,183 with an operating cost of$ 7,627 per year and a salvage value of$7,104 after4 year .at MARR of 0.12% per year find the pw of machine y?A contractor has a 4-year concrete mixer whose first cost was $6,000, having 3 more years to live before being scrapped and sold at $801. Itcould now be sold for $11,922. It has an annual cost for operation and maintenance of $9,352. Its replacement is being proposed with a newmachine whose first cost will be $8,000 having a life of 9 years and salvage value $1,600. It has an operating cost of $800 per year andmaintenance cost of $320 per year. Ifthe interest is 20% cpd-a, what is the Annual Equivalent Cost of the Old Machine? 14,792Motor A and B is providing 150hp and it is being used for 10 hours per day, 250 days in a year if the motor is using the electricity. Additional cost for both motors is the annual maintenance cost worth 1200 and other manufacturing overhead costing 550 per month. Motor A has an original price of 50,000 while 45000 for Motor B, and both have the salvage value of 3000 after 5 years. Machine efficiency is 92% and 90% respectively.A. How much is the electrical cost if the money is worth 15%? Electrical cost = pesos ( 2 decimal places ) B. With the same initial cost, salvage value, expected life, number of working days per year, annual maintenance cost and manufacturing overhead. How much is the fuel cost if the interest rate is 10% compounded annually if motor A needs to be refilled by 2L/ output while motor B requires a 3L/output, and the target output per day is 10 outputs?
- You need to determine whether a project is profitable or not in a long run. Based on the data given, which of theseprojects will be profitable according to engineering economy methods?a. θ = 3 yrs., Net Value: 0b. Accumulated (without interest) net values of the revenues, expenses and investments after 5 years is +300.c. Accumulated (without interest) net values of the revenues, expenses and investments after 4 years is +100.d. θ = 6 yrs., Net Value: +400For these two AW relations, the breakeven point QBE in miles per year is closest to:AW1=-23,000(A/P,10%,10) + 4000(A/F,10%, 10) - 5000 - 4QBEAW2 =-8000(A/P,10%,4) - 2000 - 6QBEa. 1984b. 1224c. 1090d. 655It is proposed to place a cable on existing pole line along the shore of a lake to connect two points on opposite sides. Which is more economical?Compare alternatives using the following methods:a) ROR on Additional Investment Methodb) Annual Cost Methodc) Equivalent Uniform Annual Cost Methodd) Present Worth Cost Method
- An asset has a first cost of $17000 , an annual operationg cost of $8000 and a salavage value of $5000 after 3 years. calculate the annual worth for one cycle at i=10% . (a) 32145 (b) 4376 (c) 4376 (d) 13325An iron ore of 50x10^6 ton was produced during 15 years and has been sold for $100 per ton Estimate the required investment if 0.4 turnover ratio was considered. If produced ton costs $28, what would be the net present value of the project when 8% safe rate and 15% rate of return assuming that the Investment will be depreciated within 15 years?Dexcon Technologies, Inc. is evaluating two alternatives to produce its new plastic filament with tribological (i.e., low friction) properties for creating custom bearings for 3-D printers. The estimates associated with each alternative are shown below. Using a MARR of 20% per year, which alternative has the lower present worth? Method DDM LS First cost, $ −164,000 −370,000 M&O cost, $/year −55,000 −21,000 Salvage value, $ 0 30,000 Life, years 2 4