c. Complete an ANOVA table. (Round the SS, MS, and Fvalues to 3 decimal places.)ANOVASource ofVariationDrMSTreatErrorTotalThe following hypotheses are given.Họ: H1=42 43 = 44H: The means are not all equal.d. State the decision rule for 0.05 significance level. (Round the final answer to 2 decimal places.)Reject Ho if FAt the 0.05 significance level, is there a difference in the treatment mežns?There (Cick to select) difference in the treatment means.e. Develop a 95% confidence interval for the difference in the mean amount of music time between station 1 and station 4. (Negativeanswer should be indicated by a minus sign. Round the final answers to 3 decimal places.)The 95% confidence interval is betweenandIs there a difference in the mean amount of music time between station 1 and station 47 Use the 0.05 significance level(Cick to select) SavedHelpSaveThere are four radio stations in Midland, The stations have different formats (hard rock, classical, country and western, and easylistening), but each is concerned with the number of minutes of music played per hour. From a sample of 10 hours from each station,the following sample means were offered:X = 52.77X = 50.56a. Determine SST. (Round the final answer to 3 decimal places.)X; = 45.76X = 48.58ss total - 647.00084SST =b. Determine SSE. (Round the final answer to 3 decimal places.)SSEc. Complete an ANOVA table. (Round the Ss, MS, and Fvalues to 3 decimal places.)ANOVASource ofDFVariationTreatErrorTotalThe following hypotheses are given.Ho: H1=42 - H3 - 4H: The means are not all equal.d. State the decision rule for 0.05 significance level. (Round the final answer to 2 decimal places.)Reiect Ho if F

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c. Complete an ANOVA table. (Round the SS, MS, and Fvalues to 3 decimal places.)ANOVASource ofVariationDrMSTreatErrorTotalThe following hypotheses are given.Họ: H1=42 43 = 44H: The means are not all equal.d. State the decision rule for 0.05 significance level. (Round the final answer to 2 decimal places.)Reject Ho if F>At the 0.05 significance level, is there a difference in the treatment mežns?There (Cick to select) difference in the treatment means.e. Develop a 95% confidence interval for the difference in the mean amount of music time between station 1 and station 4. (Negativeanswer should be indicated by a minus sign. Round the final answers to 3 decimal places.)The 95% confidence interval is betweenandIs there a difference in the mean amount of music time between station 1 and station 47 Use the 0.05 significance level(Cick to select) SavedHelpSaveThere are four radio stations in Midland, The stations have different formats (hard rock, classical, country and western, and easylistening), but each is concerned with the number of minutes of music played per hour. From a sample of 10 hours from each station,the following sample means were offered:X = 52.77X = 50.56a. Determine SST. (Round the final answer to 3 decimal places.)X; = 45.76X = 48.58ss total - 647.00084SST =b. Determine SSE. (Round the final answer to 3 decimal places.)SSEc. Complete an ANOVA table. (Round the Ss, MS, and Fvalues to 3 decimal places.)ANOVASource ofDFVariationTreatErrorTotalThe following hypotheses are given.Ho: H1=42 - H3 - 4H: The means are not all equal.d. State the decision rule for 0.05 significance level. (Round the final answer to 2 decimal places.)Reiect Ho if F>

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Complete an ANOVA table. (Round the SS, MS, and Fvalues to 3 decimal places.) ANOVA Source of Variation Dr MS Treat Keror Total he following hypotheses are given. o: 41 H2 H3 H4