QuestComplete and balance the following formula equation for the reaction below. Write the completeionic equation and the net ionic equation. All equations must be balanced and include phases (s, I,8.or ag).------>KOH (aq)MnBr3 (aq)Formula Eq:Total lonic:Net lonic:MacBook AirF10000F4F7F8F9F5F6F3$44%&*3678Y5

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Answered: Complete and balance the following…

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter17: Electrochemistry

Section: Chapter Questions

Problem 80AP

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Please answer this NEATLY, COMPLETELY, and CORRECTLY for an UPVOTE. Ni(NO3)2From the stock solution (1.0 M), determine the volume needed to prepare 0.00, 0.04, 0.08, 0.12 and 0.16 M Ni(NO3)2 solution in 50 mL volumetric flask. Obtain the calculated amounts, place in corresponding volumetric flasks and dilute to mark.
Arsenic(III) oxide (As2O3) is available in pure form and is a useful (but carcinogenic) primary standard for oxidizing agents such as MnO4-. The As2O3 is dissolved in base and then titrated with MnO4- in acidic solution. A small amount of iodide (I - ) or iodate (IO3-) is used to catalyze the reaction between H3AsO3 and MnO4-. As2O3 + 4 OH - 2 HAsO32- + H2OHAsO32- + 2 H+ H3AsO35 H3AsO3 + 2 MnO4- + 6 H+ 5 H3AsO4 + 2 Mn2+ + 3 H2O (a) A 3.209 g aliquot of KMnO4 (FM 158.034) was dissolved in 1.000 L of water, heated to cause any reactions with impurities to occur, cooled and filtered. What is the theoretical molarity of this solution if no MnO4- was consumed by impurities? M(b) What mass of As2O3 (FM 197.84) would be just sufficient to react with 25.00 mL of the KMnO4 solution in part (a)? g(c) It was found that 0.146 8 g of As2O3 required 29.98 mL of KMnO4 solution for the faint color of unreacted MnO4- to appear. In a blank titration, 0.03 mL of MnO4- was required to produce enough…
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MnO4- can be used in a redox titration to determine the amount of H2C2O4 in an unknown sample. Below is an unbalanced reaction that describes this process: MnO4- + H2C2O4 --> Mn2+ + CO2 25.00 mL of a solution containing an unknown amount of H2C2O4 (MW = 90.03 g/mol) required 18.31 mL of 0.1153 M MnO4- to react completely. Calculate the molarity of the original unknown H2C2O4 solution.NOTE: This is a redox titration, so remember to balance each half reaction and then add them together to arrive at the overall balanced reaction. To help you out, I will tell you that each C in H2C2O4 has a 3+ charge. Also, if your overall balanced reaction doesn't have 8 waters on the right, you have done something incorrectly.
Hydrogen peroxide solutions can easily be decomposed by dust, trace amounts of metals or light. It istherefore necessary to periodically determine the purity of the peroxide solutions.This can be done via a redox titration as follows: The density of a particular surgical grade hydrogen peroxide solution is 1.11g.cm-3. Exactly 10 mL of this solution was pipetted and quantitatively transferred, along with a sufficientamount of a dilute sulphuric acid solution, into a 250.00 mL volumetric flask and made up to the mark. A 25.00 mL portion of this diluted solution is pipetted into a conical flask, and titrated with a0.372 M KMnO4 solution. The endpoint of the titration is determined when the colourless solution in the conical flask turns apersistent bright pink due to the presence of excess permanganate ions. The average titration value is 26.20 mL of the KMnO4 solution 1.Determine the percentage of the hydrogen peroxide in the solution sample.2. Naturally occurring manganese…
Choi is fond of carbonated beverages so he crafted his own soda formulation called “Sodalicious.” Ulan, who is a fellow enthusiast, also made her own formulation which she called “Soda Pop!” to challenge his friend Choi. To know which formulation is better, they sought to determine the carbonic acid content of their soda formulations using titration. In the first part of their experiment, a 0.5 Mlabeled NaOH solution was standardized against 0.350 grams of KHP (MW = 204.22 g/mol) primary standard that is 99.6% pure. The titration required 3.16 mL of the NaOH solution to reach the phenolphthalein endpoint. In the second part of their experiment, Choi and Ulan independently prepared their samples by taking 25.0-mL of their soda sample and diluting it to 30.0 mL. Using the same titrant and indicator, Choi’s “Sodalicious” required 1.39 mL of the standardized titrant to reach the endpoint, while Ulan’s “Soda Pop!” required 0.926 mL of the same titrant to reach the endpoint. A. What is the…
Choi is fond of carbonated beverages so he crafted his own soda formulation called “Sodalicious.” Ulan, who is a fellow enthusiast, also made her own formulation which she called “Soda Pop!” to challenge his friend Choi. To know which formulation is better, they sought to determine the carbonic acid content of their soda formulations using titration. In the first part of their experiment, a 0.5 Mlabeled NaOH solution was standardized against 0.350 grams of KHP (MW = 204.22 g/mol) primary standard that is 99.6% pure. The titration required 3.16 mL of the NaOH solution to reach the phenolphthalein endpoint. In the second part of their experiment, Choi and Ulan independently prepared their samples by taking 25.0-mL of their soda sample and diluting it to 30.0 mL. Using the same titrant and indicator, Choi’s “Sodalicious” required 1.39 mL of the standardized titrant to reach the endpoint, while Ulan’s “Soda Pop!” required 0.926 mL of the same titrant to reach the endpoint. D. Calculate…
Rei and Akari, two vinegar enthusiasts, are each tasked to determine the aceticacid content of their respective vinegar concoctions by titration. First, a 1M-labeled KOH solution was standardized against the KHP (MW = 204.22 g/mol)standard that is 99.4% pure. In the process, 0.540 g KHP was found to require2.80 mL of the KOH solution to completely react up to the phenolphthaleinendpoint. Then, Rei and Akari both prepared their samples by taking 10.0-mLaliquots of each vinegar and diluting them to 25.0 mL. Using the same titrant andindicator, Rei’s vinegar required 18.60 mL of the standardized titrant to reach theendpoint, while Akari’s vinegar required 16.50 mL of the same titrant to reach thesame endpoint. What is the exact concentration of the KOH titrant in molarity? What is the balanced chemical equation between the analyte and the titrant? What is the color transition (color X color Y) expected throughout thecourse of titration? What is the acetic acid concentration of Rei’s and…
If you complete and balance the following equation in acidicsolutionMn2+(aq) + NaBiO3(s)---->Bi3+(aq)+ MnO4-(aq) + Na+(aq)how many water molecules are there in the balanced equation(for the reaction balanced with the smallest whole-numbercoefficients)? (a) Four on the reactant side (b) Three on the product side (c) One on the reactant side (d) Seven on theproduct side (e) Two on the product side
The following reactions (note that the arrows are pointingonly one direction) can be used to prepare an activity seriesfor the halogens:Br2(aq) + 2 NaI(aq)----->2 NaBr(aq) + I2(aq)Cl2(aq) + 2 NaBr(aq)----->2 NaCl(aq) + Br2(aq)(a) Which elemental halogen would you predict is the moststable, upon mixing with other halides? (b) Predict whethera reaction will occur when elemental chlorine and potassiumiodide are mixed. (c) Predict whether a reaction will occurwhen elemental bromine and lithium chloride are mixed.
Mark and John, two vinegar enthusiasts, are each tasked to determine the acetic acid content of their respective vinegar concoctions by titration. First, a 1 M-labeled KOH solution was standardized against the KHP (MW = 204.22 g/mol) standard that is 99.4% pure. In the process, 0.540 g KHP was found to require 2.80 mL of the KOH solution to completely react up to the phenolphthalein endpoint. Then, Mark and John both prepared their samples by taking 10.0-mL aliquots of each vinegar and diluting them to 25.0 mL. Using the same titrant and indicator, Mark’s vinegar required 18.60 mL of the standardized titrant to reach the endpoint, while John’s vinegar required 16.50 mL of the same titrant to reach the same endpoint. Question: What is the acetic acid concentration of Mark’s and John’s vinegar in molarity given that the Concentration of KOH is 9386 M?
Mark and John, two vinegar enthusiasts, are each tasked to determine the acetic acid content of their respective vinegar concoctions by titration. First, a 1 M-labeled KOH solution was standardized against the KHP (MW = 204.22 g/mol) standard that is 99.4% pure. In the process, 0.540 g KHP was found to require 2.80 mL of the KOH solution to completely react up to the phenolphthalein endpoint. Then, Mark and John both prepared their samples by taking 10.0-mL aliquots of each vinegar and diluting them to 25.0 mL. Using the same titrant and indicator, Mark’s vinegar required 18.60 mL of the standardized titrant to reach the endpoint, while John’s vinegar required 16.50 mL of the same titrant to reach the same endpoint. Question: What is the exact concentration of the KOH titrant in molarity? What is the balanced chemical equation between the analyte and the titrant? What is the color transition (color X ? color Y) expected throughout the course of titration?

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Complete and balance the following formula equation for the reaction below. Write the complete ionic equation and the net ionic equation. All equations must be balanced and include phases (s. I. g.or ag). КОН (ag) MnBr3 (aq) -- -> Formula Eq: --- Total lonic: Net lonic: