Complete and balance the following redox equations using the smallest whole-number coefficients. The reaction takes place in a BASIC solution. CrO42–(aq) + Cu (s) → Cr(OH)3 (s) + Cu(OH)2 (s) In the balanced equation, 3 molecules of water are present on the product side. In the balanced equation, 3 molecules of water are present on the reagent side. In the balanced equation, 4 OH- are present on the reagent side. In the balanced equation, 4 OH- are present on the product side. In the balanced equation, 5 molecules of water are present on the product side. In the balanced equation, 5 molecules of water are present on the reagent side.
Complete and balance the following redox equations using the smallest whole-number coefficients. The reaction takes place in a BASIC solution. CrO42–(aq) + Cu (s) → Cr(OH)3 (s) + Cu(OH)2 (s) In the balanced equation, 3 molecules of water are present on the product side. In the balanced equation, 3 molecules of water are present on the reagent side. In the balanced equation, 4 OH- are present on the reagent side. In the balanced equation, 4 OH- are present on the product side. In the balanced equation, 5 molecules of water are present on the product side. In the balanced equation, 5 molecules of water are present on the reagent side.
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter21: The Chemistry Of The Main Group Elements
Section: Chapter Questions
Problem 131SCQ: Xenon trioxide, XeO3, reacts with aqueous base to form the xenate anion, HXeO4. This ion reacts...
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Complete and balance the following redox equations using the smallest whole-number coefficients. The reaction takes place in a BASIC solution.
CrO42–(aq) + Cu (s) → Cr(OH)3 (s) + Cu(OH)2 (s)
In the balanced equation, 3 molecules of water are present on the product side.
In the balanced equation, 3 molecules of water are present on the reagent side.
In the balanced equation, 4 OH- are present on the reagent side.
In the balanced equation, 4 OH- are present on the product side.
In the balanced equation, 5 molecules of water are present on the product side.
In the balanced equation, 5 molecules of water are present on the reagent side.
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