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Complete the table. Calculate the cell potential when 20.0 mL of 0.05 M Fe2+ was titrated with 0.05 M Ce4+ in a matrix of 1 M. HCL04. Answers should be in 3 decimal points. Write the values only, no need for units. The reaction is given as Fe2* +Ce4+ Ce3+ +Fe+ Standard Potentials are Fe3+ +e- →FE2+ Eo =+0.767 V and Ce +e-Ce* Eo =+1.70 V

Complete the table. Calculate the cell potential when 20.0 mL of 0.05 M Fe2+ was titrated with 0.05 M Ce4+ in a matrix of 1 M. HCL04. Answers should be in 3 decimal points. Write the values only, no need for units. The reaction is given as Fe2* +Ce4+ Ce3+ +Fe+ Standard Potentials are Fe3+ +e- →FE2+ Eo =+0.767 V and Ce +e-Ce* Eo =+1.70 V

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter17: Electrochemistry And Its Applications
Section: Chapter Questions
Problem 38QRT
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Vt 10mL 15mL 20mL 25mL 30mL
Transcribed Image Text:Vt 10mL 15mL 20mL 25mL 30mL
Complete the table. Calculate the cell potential when 20.0 mL of 0.05 M Fe2t was titrated with 0.05 M Ce+ in a matrix of 1 M HCLO4. Answers should be in 3 decimal points. Write the values only, no need for units. The reaction is given as Fe2+ +Ce4+ Ce+ +Fe+ Standard Potentials are Fes+ +e- →FE2+ Eo =+0.767 V and Ce +e- →Ce Eo =+1.70 V
Transcribed Image Text:Complete the table. Calculate the cell potential when 20.0 mL of 0.05 M Fe2t was titrated with 0.05 M Ce+ in a matrix of 1 M HCLO4. Answers should be in 3 decimal points. Write the values only, no need for units. The reaction is given as Fe2+ +Ce4+ Ce+ +Fe+ Standard Potentials are Fes+ +e- →FE2+ Eo =+0.767 V and Ce +e- →Ce Eo =+1.70 V
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