given the following info please provide a strucutre, the one I gave is incorrect. Compound A has a molecular formula of C,H0. What is the Unsaturation Number (UN) or Double-BondEquivalent (DBE)?UN/DBE:Based on the UN/DBE you calculated, could there be a double bond in compound A?yesnoBased on the UN/DBE you calculated, could there be a ring in compound A?yesnoBased on the molecular formula and the UN/DBE you calculated, check all the functional groups that could be present incompound A.O esterV alcoholO ringO benzene ringO ketoneO nitrileO alkyneO carboxylic acidO amineО ерохideV etherO alkeneO aldehydeExamine the IR spectrum provided for compound A.The peak at ~3300 is due to residual amount of water in the sample and therefore it will not be considered.The peaks below 1500 cannot be used to make any structural assignments because they are in the fingerprint region.In this IR spectrum you should focus on the peak ~2900-3000.What is this peak most likely due to?O C-H (sp)C-H (sp?)C=0C-H (sp³)OC-O or N-0O 0-H or N-HEarlier, usingmolecularandUN/DBE, you came up with ational groupscould be present incompound A. Now, using the IR data you should be able to narrow this list.Check all the functional groups that could be present in compound A.O nitrileO epoxideO amine| ketoneO benzene ringO aldehydeO alkyneO alcoholO alkeneO ringO carboxylic acidV etherI esterCarbon spectra say a lot about the symmetry of the molecule. If two carbons in a molecule are equivalent (such as in anisopropyl group) they only produce one signal in the spectrum. Although carbon signals cannot be integrated, the relativesize of peaks in the carbon spectrum can help determine how many equivalent carbons are present in a single signal.Compare the number of signals in the spectrum and the number of carbons from the molecular formula for compound A.Which of the given statements is true?O All the carbons are nonequivalent.O Two of the carbons are equivalent.Three of the carbons are equivalent.Four of the carbons are equivalent.Evaluate the spectrum for compound A based on what you already know from the UN/DBE and IR spectrum.Is the 13C spectrum consistent with the presence of an ether functional group?О yesO noExamine the 'H spectrum of compound A.There is a table summarizing the spectral data. Using that data, assign each peak to the type of alkyl group.ppmIntegrationSplittingA3.702HsingletВ3.303Hsinglet1.259 HsingletAВCa methylene – CH,a methyl – CH,a tert-butyl group - C(CH,),Answer Banka methyne – CHNow, after you have determined what kind of fragments are present in the molecule, the next step will be to think about howyou would connect these fragments.CH3Hsc -ć - 0-C -CHSO O

Compound A has a molecular formula of C,H0. What is the Unsaturation Number (UN) or Double-Bond Equivalent (DBE)? UN/DBE: Based on the UN/DBE you calculated, could there be a double bond in compound A? yes no Based on the UN/DBE you calculated, could there be a ring in compound A? yes no Based on the molecular formula and the UN/DBE you calculated, check all the functional groups that could be present in compound A. | ester V alcohol O ring O benzene ring O ketone O nitrile O alkyne O carboxylic acid O amine О ерохide V ether O alkene O aldehyde Examine the IR spectrum provided for compound A. The peak at ~3300 is due to residual amount of water in the sample and therefore it will not be considered. The peaks below 1500 cannot be used to make any structural assignments because they are in the fingerprint region. In this IR spectrum you should focus on the peak ~2900-3000. What is this peak most likely due to? O C-H (sp) C-H (sp?) C=0 C-H (sp') OC-O or N-0 О 0-Hor N-н O O

Compound A has a molecular formula of C,H0. What is the Unsaturation Number (UN) or Double-Bond Equivalent (DBE)? UN/DBE: Based on the UN/DBE you calculated, could there be a double bond in compound A? yes no Based on the UN/DBE you calculated, could there be a ring in compound A? yes no Based on the molecular formula and the UN/DBE you calculated, check all the functional groups that could be present in compound A. | ester V alcohol O ring O benzene ring O ketone O nitrile O alkyne O carboxylic acid O amine О ерохide V ether O alkene O aldehyde Examine the IR spectrum provided for compound A. The peak at ~3300 is due to residual amount of water in the sample and therefore it will not be considered. The peaks below 1500 cannot be used to make any structural assignments because they are in the fingerprint region. In this IR spectrum you should focus on the peak ~2900-3000. What is this peak most likely due to? O C-H (sp) C-H (sp?) C=0 C-H (sp') OC-O or N-0 О 0-Hor N-н O O

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter6: Alkanes & Alkenes

Section: Chapter Questions

Problem 21E

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Similar questions

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