Compound has molecular formula C10H1804 and shows the following spectral data: IR (on"): 2950, 1740 (strong), a) 'H NMR signal #19 chem, shiffondtiplicity ratio (ppm) 4.3 septet 1 2 3 2.6 Singlet 2 1.1 doublet 6 Which one of the following structures is consistent with the spectral date? d 3 b) HO OH 2 @ yo C 3 5.d 60
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- Thymol (molecular formula C10H14O) is the major component of the oil ofthyme. Thymol shows IR absorptions at 3500–3200, 3150–2850, 1621, and1585 cm−1. The 1H NMR spectrum of thymol is given below. Propose apossible structure for thymol.Compounds B and C are isomers with molecular formula C5H9BrO2. The 1H NMR spectrum of compounds B and C are shown below. The IR spectrum corresponding to compound B showed strong absorption bands at 1739, 1225, and 1158 cm-1, while the spectrum corresponding to compound C have strong bands at 1735, 1237, and 1182 cm-1. 1.Based on the information provided, determine the structure of compounds B and C. 2.Assign all peaks in 1H NMR spectrum of compounds B and C.Propose a structure for the compound that fits the following description. C10H14 7.18 δ, (4H, broad singlet) 2.70 δ (4H, quartet J = 7 Hz) 1.20 δ (6H. triplet J = 7 Hz) IR: 745 cm-1 7(a) IR absorption indicate the compound is .........-disubstituted = 7(b) The name of the compound is =
- The unknown compound with molecular formula C4H8O3, has infrared absorptions at 1710 and 2500 to 3100 cm^-1 and has ¹H NMR spectrum shown. Analyze the given data and propose a structure for this compound. Explain how you come up with your proposed compound.Compound p,c6h14O does not react w/sodium metal,doesn't discharge the color of Br2 in ccl4, the H-NMR spectrum shows 2 signal,a 12H doublet at 1.1, and a 2h sextet at 3.6. Propose a structure for this compound,p.A compound of formula C6H10O2 shows only two absorptions in the proton NMR: a singlet at 2.67 ppm and a singlet at2.15 ppm. These absorptions have areas in the ratio 2:3. The IR spectrum shows a strong absorption at 1708 cm-1. Proposea structure for this compound.
- Use the 1H NMR and IR spectra given below to identify the structure ofcompound B (molecular formula C4H8O2).Reaction of C6H5CH2CH2OH with CH3COCl affords compound W, whichhas molecular formula C10H12O2. W shows prominent IR absorptions at3088–2897, 1740, and 1606 cm−1. W exhibits the following signals in its1H NMR spectrum: 2.02 (singlet), 2.91 (triplet), 4.25 (triplet), and 7.20–7.35(multiplet) ppm. What is the structure of W?A solution of acetone [(CH3)2C=O] in ethanol (CH3CH2OH) in the presence of a trace of acid was allowed to stand for several days, and a new compound of molecular formula C7H16O2 was formed. The IR spectrum showed only one major peak in the functional group region around 3000 cm−1, and the 1H NMR spectrum is given here. What is the structure of the product?
- A reaction with compound X (C8H15OCl) with water produces a product which has an absorbance in the IR spectrum at 1800 and 3500 cm-1. What fictional group is present?Compound Y (molecular formula C6H10) gives four lines in its 13C NMRspectrum (27, 30, 67, and 93 ppm) and the IR spectrum given here.Propose a structure for Y. Additional spectroscopy problems on alkynes are given in Chapters B and C:Infrared spectroscopy: B.4a; B.5; B.16a; B.19a; B.21a, d; B.29Nuclear magnetic resonance spectroscopy: C.12aCompound C has molecular formula C5H8O. The IR, mass, 1H-NMR, and 13C-NMR spectra are shown below. Suggest a structure for C and explain your reasoning.