Compounds X and Y are both C,H15CI products formed in the radical chlorination of 2,4-dimethylpentane.Base-promoted E2 elimination of X and Y gives, in each case, a single C-H14 alkene.Both X and Y undergo an SN2 reaction with sodium iodide in acetone solution to give C-H151 products; in this reactionY reacts faster than X.What is the structure of X?• Do not use stereobonds in your answer.• In cases where there is more than one possible structure for each molecule, just give one for each.• Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom rightcorner.Separate structures with + signs from the drop-down menu.In (FChemDoodle

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Compounds X and Y are both C,H15CI products formed in the radical chlorination of 2,4-dimethylpentane. Base-promoted E2 elimination of X and Y gives, in each case, a single C,H14 alkene. Both X and Y undergo an SN2 reaction with sodium iodide in acetone solution to give C7H151 products; in this reaction Y reacts faster than X. What is the structure of X?

Compounds X and Y are both C,H15CI products formed in the radical chlorination of 2,4-dimethylpentane. Base-promoted E2 elimination of X and Y gives, in each case, a single C,H14 alkene. Both X and Y undergo an SN2 reaction with sodium iodide in acetone solution to give C7H151 products; in this reaction Y reacts faster than X. What is the structure of X?

Organic Chemistry

8th Edition

ISBN:9781305580350

Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Chapter9: Nucleophilic Substitution And Β-elimination

Section9.7: Experimental Evidence For E1 And E2 Mechanisms

Problem 9.7P

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