KHW #1 - OscillationsConceptual Question 14.8A mass hanging from a spring undergoes vertical simpleharmonic motion.aboveWhere in the motion is the spring force equal to zero?Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence iscomplete before submitting your answer.mg/k below2mg/k belowsmalllarge2mg/k abovemg/k abovebelowSubmit Previous Answers Request AnswerMacBook ProReset HelpIn order for the spring to exert no restoringforce at all, the oscillation would have to be solarge that the highest point is at or abovethe initial, unweighted equilibrium end of thespring. In this case, as the mass passesthrough the point where the unstretched end ofthe spring would hang if unweighted, the springwould momentarily exert no force on the mass.X Incorrect; Try Again; 3 attempts remainingPearsonThe new equilibrium point is a distance2mg/k above the initial unstretched bottomof the spring, where m is the mass of thehanging object and k is the spring constant.< 2 of 13Review | Constants Course Home

Name: KHW #1 - OscillationsConceptual Question 14.8A mass hanging from a sp
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Description: KHW #1 - OscillationsConceptual Question 14.8A mass hanging from a spring undergoes vertical simpleharmonic motion.aboveWhere in the motion is the spring force equal to zero?Match the words in the left column to the appropriate blanks in the sentenc

Simple harmonic motion (SHM) is a type of periodic motion where the restoring force is directly…

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Conceptual Question 14.8 A mass hanging from a spring undergoes vertical simple harmonic motion. lowest point Where in the motion does the acceleration have its greatest magnitude? Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer. the smallest highest point the greatest highest or lowest points new, weighted equilibrium point Reset Help The acceleration has its greatest magnitude as the mass passes through its highest or lowest points. We know this <2 of 13 > because this is where the spring has the the greatest stretch from its new equilibrium position. This means the net force is the greatest there, and thus the acceleration. is lowest point Review 1 Constants