Consider a 5.00m long ladder, with a mass of 25.0kg that can be approximated as uniformly distructed. The ladder is standing at an angle of 70 degrees to the horizontal, leaning against a wall. There is a person weighing 80.0kg that is standing 2.00m up along the ladder's length. If the force of the all is directly horizontal, calculate the force of friction between the ground and the ladder that's required to keep it from slipping(Hint: assume net torque about the ground is 0, and use that to calculate the force in magnitude) b) If the ladder was instead at an angle of 45 degrees to the horizontal, would the frictional force required be greater, equal or the same? Explain
Consider a 5.00m long ladder, with a mass of 25.0kg that can be approximated as uniformly distructed. The ladder is standing at an angle of 70 degrees to the horizontal, leaning against a wall. There is a person weighing 80.0kg that is standing 2.00m up along the ladder's length. If the force of the all is directly horizontal, calculate the
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
