Consider a car that is initially traveling along a straight stretch of highway at 15 m/sm/s. At t=0t=0 the car begins to accelerate at 2.0 m/s2m/s2 in order to pass a truck. The final velocity is vx=25m/svx=25m/s. Calculate how far the car travels during its 5.0 ss of acceleration.
Consider a car that is initially traveling along a straight stretch of highway at 15 m/sm/s. At t=0t=0 the car begins to accelerate at 2.0 m/s2m/s2 in order to pass a truck. The final velocity is vx=25m/svx=25m/s. Calculate how far the car travels during its 5.0 ss of acceleration.
Physics for Scientists and Engineers
10th Edition
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter1: Physics And Measurement
Section: Chapter Questions
Problem 26P: Review. Prove that one solution of the equation 2.00x43.00x3+5.00x=70.0 is x = 2.22.
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Consider a car that is initially traveling along a straight stretch of highway at 15 m/sm/s. At t=0t=0 the car begins to accelerate at 2.0 m/s2m/s2 in order to pass a truck. The final velocity is vx=25m/svx=25m/s. Calculate how far the car travels during its 5.0 ss of acceleration.
Expert Solution
Step 1
SOlution:
Given that
initial velocity, u = 15 m/s
final velocity, v = 25 m/s
acceleration, a = 2 m/s2
time t = 5 s
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