Consider a closed triangular box resting within a horizontal electric field of magnitude E = 8.86 x 10 N/C as shown in the figure below. 30.0 ст E 60.0° 10.0ст (a) Calculate the electric flux through the vertical rectangular surface of the box. 2.66 This is the correct magnitude, but what is the direction of the normal vector for this surface? kN m²/C (b) Calculate the electric flux through the slanted surface of the box. 4.6 Does any field line that passes through the vertical surface also pass through the slanted surface? kN • m2/c (c) Calculate the electric flux through the entire surface of the box. 7.26 You are correct that the total flux should be the sum of the fluxes through the first two surfaces. kN · m²/C
Consider a closed triangular box resting within a horizontal electric field of magnitude E = 8.86 x 10 N/C as shown in the figure below. 30.0 ст E 60.0° 10.0ст (a) Calculate the electric flux through the vertical rectangular surface of the box. 2.66 This is the correct magnitude, but what is the direction of the normal vector for this surface? kN m²/C (b) Calculate the electric flux through the slanted surface of the box. 4.6 Does any field line that passes through the vertical surface also pass through the slanted surface? kN • m2/c (c) Calculate the electric flux through the entire surface of the box. 7.26 You are correct that the total flux should be the sum of the fluxes through the first two surfaces. kN · m²/C
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter15: Electric Forces And Fields
Section: Chapter Questions
Problem 49P: Figure P15.49 shows a closed cylinder with cross-sectional area A = 2.00 m2. The constant electric...
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