Consider a function f : R² → R where f(x, y) = (1 + x²)e²v for all (æ, y) E R². Apply the second-order Taylor approximation around (0,0) to estimate f(-0.1,0.2). (You do not have

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Consider a function f : R² → R where f(x, y) = (1 + x²)e²v for all (æ, y) E R². Apply the
second-order Taylor approximation around (0,0) to estimate f(-0.1,0.2). (You do not have
Transcribed Image Text:Consider a function f : R² → R where f(x, y) = (1 + x²)e²v for all (æ, y) E R². Apply the second-order Taylor approximation around (0,0) to estimate f(-0.1,0.2). (You do not have
Expert Solution
Step 1

For a function f:2 i.e. f(x,y), the second-order Taylor approximation at a point (a,b) is defined as

f(x,y)=f(a,b)+fx(a,b)(x-a)+fy(a,b)(y-b)+12fxx(a,b)(x-a)2+fxy(a,b)(x-a)(y-b)+12fyy(a-b)y-b2

where fx(a,b) is the partial derivative of the function at the point (a,b).

Step 2

Given: f(x,y)=(1+x2)e2y, (a,b)=(0,0)

On differentiating f(x,y) partially with respect to x we get

fx(x,y)=2xe2y

On differentiating this partially with respect to y we get

fxy(x,y)=4xe2y

On differentiating this again partially with respect to x we get

fxx(x,y)=2e2y

On substituting (x,y)=(a,b) we get x we get

fx(0,0)=0

fxy(0,0)=0

fxx(0,0)=2

On differentiating f(x,y) partially with respect to y we get

fy(x,y)=2(1+x2)e2y

On differentiating this again partially with respect to y we get

fy(x,y)=4(1+x2)e2y

On substituting (x,y)=(a,b) we get

fy(0,0)=2

fyy(0,0)=4

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