Consider an ice-producing plant that operates on the ideal vapor-compression refrigeration cycle and uses refrigerant-134a as the working fluid. The refrigeration cycle operating conditions require an evaporator pressure of 180 kPa and the condenser pressure of 1400 kPa. Cooling water flows through the water jacket surrounding the condenser and is supplied at the rate of 250 kg/s. The cooling water has a 10°C temperature rise as it flows through the water jacket. To produce ice, potable water is supplied to the chiller section of the refrigeration cycle. For each kg of ice produced, 333 kJ of energy must be removed from the potable water supply. (Take the required values from saturated refrigerant-134a tables.) Determine the mass flow rate of the refrigerant, in kg/s. Take cp of water as 4.18 kJ/kg·K. (You must provide an answer before moving on to the next part.) The mass flow rate of the refrigerant is _________kg/s.

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Asked Apr 10, 2019
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Consider an ice-producing plant that operates on the ideal vapor-compression refrigeration cycle and uses refrigerant-134a as the working fluid. The refrigeration cycle operating conditions require an evaporator pressure of 180 kPa and the condenser pressure of 1400 kPa. Cooling water flows through the water jacket surrounding the condenser and is supplied at the rate of 250 kg/s. The cooling water has a 10°C temperature rise as it flows through the water jacket. To produce ice, potable water is supplied to the chiller section of the refrigeration cycle. For each kg of ice produced, 333 kJ of energy must be removed from the potable water supply.

 

(Take the required values from saturated refrigerant-134a tables.)

 

Determine the mass flow rate of the refrigerant, in kg/s. Take cp of water as 4.18 kJ/kg·K. (You must provide an answer before moving on to the next part.)

 

The mass flow rate of the refrigerant is _________kg/s.

 
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Expert Answer

Step 1

Refrigerant is R-134a

Evaporator pressure P1 = P4 = 180 kPa

Condenser pressure P2 = P3 = 1200 kPa

Mass flow rate of water mw = 250 kg/s

Rise in water temperature = 10oC

For 1 kg of ice, energy to be removed = hfg = 333 kJ/kg

Step 2

Process 4-1 shows the production of ice taking place in the evaporator, where 333 kJ of energy is removed for each kg of ice produced.

Process 2-3 shows the cooling of condenser through a water jacket.  

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Step 3

From the energy balance equation, the amount of heat removed at the evaporator to produce ice will be equal to the amo...

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