Consider open channel of water depth h=0.5 m, channel slope §=0.0005 where fully-developed boundary layer is established (see figure below). u(2) ZA 50
Q: 4. Estimate the wetted area of a triangular channel having a depth of 5m and the side slope is…
A: To find : Wetted area.
Q: Determine the critical depth (m) for following rectangular open channel: Flowrate = 64 m^3/s Channel…
A: Given that: A rectangular channel, with flow rate, Q=64 m3/sChannel width, B=6m
Q: In a rectangular channel, two reaches M and N are in series, with reach M being upstream of reach N.…
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Q: Find the base width and water depth of a trapezoidal channel with side slopes of 1.5 horizontal to 1…
A: Solution:- Given data: Side slope = 1.5H:1V, Manning constant =0.030 Bed slope = 1:1666,…
Q: Find the hydraulic radius of rectangular channel having wetted area 16 m2 anc wetted perimeter 12 m
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Q: 9. Calculate the wetted perimeter for a rectangular channel having top width of 4.5m and depth of…
A: To find : Wetted perimeter.
Q: Home Work Check the stability of the gravity dam section shown in Figure at the section AA' assuming…
A: We have to check the stability of the gravity dam section shown in the figure according to the given…
Q: Determine the critical depth in meters for Trapezoidal channel. Base width = 5m Side Slope 2H:3V…
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Q: Determine the hydraulic depth D (average depth) of a triangular channel with right angle corner…
A: Y=3m
Q: Estimate the lag time (hr) for the following watershed: Hydraulic length (km) - 3.04 Curve number 60…
A: Given data:Hydraulic length(L)=3.04 km=9973.753 ft.Curve number(CN)=60 Average land slope(S)=1.1%
Q: Determine the bed slope of a trapezoidal channel has depth of flow is 1.2m and velocity of flow is…
A: Depth of the flow = y = 1.2m Velocity of the flow = v = .35m/sec Manning's coefficient = n =…
Q: A rectangular channel width 3 m, Q 25 m /sec and depth of flow is 0.5 m. At a certain section width…
A: solution Given at section 1 width of the rectangular channel B1=3 mts Q=25 m3sec and depth…
Q: 4. What is the culvert bottom slope denoted as? a) sl b) SL c) So d) sL
A: The culvert bottom slope denoted as c) So Other , options doesn't exist. Correct option is C
Q: 2)/ Design the bed slope for most economical secti a trapezoidal channel with flow velocity of ( 2…
A: V = 2m/sec Q = 5m3/sec n = 0.022 It has been asked in the question to determine the bed slope
Q: 2. For a trapezoidal channel with a bottom with of 6 m, side slope of 3 horizontal to 1 vertical,…
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Q: A rectangular channel with a width of B = 2 m drains water with a discharge of Q = 2,4 m3/s. The…
A: Width of channel (B) = 2m Depth at upstream = 1.5m Area= 2 x 1.5 =3m2 Discharge = 2.4 m3/s Perimeter…
Q: Flow enters a long, rectangular channel at its upstream end from under a sluice gate. The channel…
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Q: A rectangular channel has a base width of 7 m and a depth of 2.5 m carries a discharge of 21.81 m…
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Q: Through the smooth transition between two rectangular channels the width increases from 3.0 m to 3.6…
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Q: Hydraulic mean depth of a rectangular channel having Width as 2 m and flow depth 50 cm 0.333 0.222
A: H=Wetted AreaWetted PerimeterWetted Area=2m×0.5m=1m2Wetted Perimeter=0.5×2+2=3m
Q: trapezoidal channel with these conditions: Left side slope = 3H:2V Right side slope = vertical…
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Q: Water is to flow at a rate of 20 m/s in the following channel (roughness 0.03). Find the vertical…
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Q: Problem 4. A trapezoidal channel has a bottom width of 6 m and side slope of 2:1. If the depth of…
A: Given: The bottom width B, is 6 m. The depth of flow y, is 1.2 m. The flow Q, is 20.40 m3/s Side…
Q: Find the value of cross sectional area of channel having discahrge value is 20 m3/s and flow…
A: Introduction : The given question is related with fluid mechanics . In this question we are provided…
Q: A trapezoidal channel has a base width of 6 m and slide slopes at 350 from the horizontal. What will…
A: For the flow in canal we design cross section of various shapes like trapezoidal, triangular,…
Q: 4. Estimate the wetted area of a triangular channel having a depth of 5m and the side slope is…
A: We have to determine the value of wetted area of the given triangular channel section having depth…
Q: 1. A trapezoidal channel with a 5-m bottom width and side slope m = 1.0 discharges 35 m'/s. The…
A: The given trapezoidal channel has following characteristics: B=5 m m=1 S=0.004 n=0.012 Q=35 m3/s
Q: Find the velocity and discharge through a trapezoidal channel of 1.5 m wide and side slopes of 1.5…
A: Solution Given Data B=1.5 my= 1.2 mManning's conatant n=0.025S=12500
Q: Find the hydraulic radius Wetted area=6.25 m2 Wetted perimeter=7.5 m
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Q: trapezoidal channel section having base 8m, depth 4m and the hydraulic radius is 2.36m. the side…
A:
Q: The ratio between maximum discharge and top width of a rectangular channel is 1.82. Calculate the…
A: given data: C=50 S=1:3000 QB=1.82
Q: Q33. Determine the economical cross-section for an open channel of trapezoidal section with side…
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Q: Q. Determine the depth in a trapezoidal channel with side slopes of 1 to 1.5, a bottom width of 8 m…
A: Given that: A trapezoidal channel withside slope, m=1.5Bed width, B=8mDischarge, Q=56 m3/sChannel…
Q: Question 22 Determine the critical depth in meters for rectangular channel. Base width = 9m…
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Q: The flow rate in a wide rectangular open channel is 2.0m²/s per meter width. The channel bed slope…
A: Given- rectangular open channel-flow rate q=2 m2/s/mbed slope S=0.002Manning's roughness coefficient…
Q: 1. Water flows uniformly in a rectangular, concrete, open channel that is 10m wide at a depth of 3…
A: Solution:- Velocity and Discharge
Q: A trapezoidal channel has a bottom width of 1m and side slopes of 2H:1V. If the depth of flow is 4…
A:
Q: a) A trapezoidal weedy excavated earth channel has a bottom slope of 1°, base width of 5 m and a…
A:
Q: 5. Determine the hydraulic depth of a riangular channel having the side slope Z and depth y.
A: To find : Hydraulic depth.
Q: Determine the critical depth in meters for Trapezoidal channel. Base width = 5m Side Slope 2H:3V…
A: Critical depth is as below:
Q: Question 5 Determine the section factor (Z) of a triangular channel with right angle corner (90°)…
A:
Q: The area of a channel section is 8m2 and the wetted perimeter is 8m. if the discharge is 33.33m/s…
A: Area A=8m2 Perimeter P=8m Discharge Q=33.33m3/ n=0.012
Q: A trapezoidal channel with lower base 2.5m has a normal depth of water 1.2m. The sides of the…
A: Discharge in the channel is defined as the volume of water flow per unit time. The discharge of the…
Q: A drainage canal in the shape of trapezoid with a bottom width of 2,3m and a side slope of 1…
A:
Q: Design a semi-circular open channel (n=0.014) that is anticipated to convey 20cumecs of water. The…
A: Given data: Q= 20cumecs slope of the channel bed = 0.0015 n=0.014 It is asked to design the…
Q: A drainage canal in the shape of trapezoid with a bottom width of 2.3m and a side slope of 1…
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Q: A trapezoidal channel of bed width 12.0 m, side slopes 2:1, longitudinal bed slope = 10 cm/km,…
A: The normal depth is the uniform depth of the channel when the slope of the channel and the water…
Q: Design a semi-circular open channel (n=0.014) that is anticipated to convey 25cumecs of water. The…
A:
Q: The coefficient of permeability below a dam is 12 m/day. The water in the upstream side is 32 meter…
A:
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- 1. Boundary layer thickness, displacement thickness and momentum thickness2. Mean velocity profile in outer scaling3. Mean turbulent stresses in outer scaling4. Calculate the shear velocity and plot the mean velocity in inner scaling. Explain how youobtained the shear velocity.5. Turbulence quantities in inner scaling and compare the profiles to a standard boundarylayer profile of the same quantity from literature. Table nomenclature:y – wall normal distance in m, first value denotes the measurement very close to the upperedge of the water flow with a depth of 0.136 mU – streamwise velocity at any y location in m/su’ – streamwise fluctuationsv’ – wall normal fluctuationsOverbar denotes the mean quantity, and the dimensions are in SI units11. A channel runs almost parallel to a river as shown in the figure. The water level in the river has an elevation of 36 m. and the elevation of the channel is 33 m. The river and channel are 600 m apart and a previous formation of the average thickness of 9 m and hydraulic conductivity of 0.80 m/hr joints them together. Compute the hydraulic gradient Compute the rate of seepage flow from the river to the channel per meter width in liters per day. If the seepage velocity is 0.048 m/day, compute the void ratio of the previous medium.The tank shown in the figure is 3 m wide into the paper. Neglect atmospheric pressure. Use ?????? = 9.79 kN/m³. Determine the following: A. vertical component of the total hydrostatic force on the quarter circle panel AB in kN B. Resultant hydrostatic force acting on the quarter circle panel AB in kN C. Angle that the resultant hydrostatic force make with the horizontal in degrees.
- Water flows in a rectangular channel of width, w. In some cases, the water may suddenly increase in elevation as shown in the figure (from h1 to h2) through a highly disturbed region called a hydraulic jump. Assume the velocity is uniform at stations 1 and 2, and assume the pressures are distributed hydrostatically. (a) Using the conservation of mass and momentum, find the equation (cubic) for the downstream depth, h2, in terms of h1, V1, and g. (b) Using the Bernoulli equation and whatever other necessary equation(s), find the equation (cubic) for the downstream depth, h2, in terms of h1, V1, and g. In light of (a) and (b) above, does your answer to this part make sense? Explain.(c) For h1 = 1 m and V1 = 7:6 m/s, find the downstream height, h2, using whichever of the above approaches is the most correct. (Note that there are two valid solutions - explain.) What is the downstream velocity?Problem 4: Consider again Problem 3 with a constant pressure gradient (Fig. 5) in the x-direction (dp/dx) and: a) Simplify the governing equations (continuity and momentum) for the flow;b) Apply the boundary conditions and determine the velocity profile;c) Develop expressions for the flow rate and mean velocity from the velocity profile. ignore anything that referenes drilling engineering (i.e. part D). I realize there isn't a drilling engineering expert but that isn't the point of the question either.. Problem 3 is attached for reference.Geotechnical Engineering Calculate Pressure and Force:a) Active Rankine Ka statusb) Passive state of Rankine, Kp
- A manometer with diameters L and d is used to measure the pressure difference P1 − P2. Both ends experienceatmospheric pressure. Completely derive the correct expression for the pressure difference:The open tank filled with a liquid in full as shown in the figure below has the height of h = 6.00 m. The inclined angle of the inclined wall is = 45.00 °. The width (perpendicular to the screen) of the inclined wall is w = 20.00 m. The specific weight of the liquid is = 9.81 kN/m3. (3) For the inclined wall, determine the vertical depth to the center of pressure._________ (m)Water flows at 2 m / s in a 3 m wide 2.5 m deep rectangular channel. There is a 1.10 m elevation on the downstream side of the channel as seen in the figure. Above the elevation, the channel widens to 3.75 m as shown in the figure If b2 = 3.75 m, what should be the maximum value of Δz to prevent suffocation? Draw the specific energy depth curve.
- From the given figure. Determine the total active lateral pressure at the interface in kPa.1. A concrete dam retaining water is show in the figure. If the specific weight of concrete is 23.5 KN/m^3. What is the factor of safety against overturning? Find the location of the resultant. Find the maximum intensity pressure. Determine the minimum intensity pressure.The hydraulic gradient is a rock that is porous and permeable enough to transmit water easily. b the difference in hydraulic head between two points, divided by the distance between them. c rock that is low in permeability so that water flows very slowly through it. d a relationship of groundwater flow rate between two point to the difference in hydraulic head between them. 2. An artesian well is one in which a pressurized groundwater rises from a deep, unconfined aquifer. b water rises above the top of the confined aquifer without any pumping. c the well is horizontal and the water table is perched. d Paint colors are mixed. e the water is warm, fairly saline, and recharged by an affluent stream. 3. A cone of depression is a a solid or hollow object which tapers from a circular or roughly circular…