Consider some copper beads that are initially at T, = 200 °C, with each bead having a mass of m, = 1.00 g. Consider also a bucket of water (m, = 1.00 kg) that is initially at T2 = 20.0°C. Suppose you want to raise the temperature of the bucket of water to T, i.e., by dropping N number of copper beads into the water. (Note: Subscript 1 represents copper beads, subscript 2 represents water. Neglecting any energy transfer to or from the container.)

Principles of Physics: A Calculus-Based Text
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Chapter16: Temperature And The Kinetic Theory Of Gases
Section: Chapter Questions
Problem 69P: Consider an object with any one of the shapes displayed in Table 10.2. What is the percentage...
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Consider some copper beads that are initially at
T, = 200 °C, with each bead having a mass of m,
= 1.00 g. Consider also a bucket of water (m, =
1.00 kg) that is initially at T2 = 20.0°C. Suppose
you want to raise the temperature of the bucket of
water to T, i.e., by dropping N number of copper
1
beads into the water.
(Note: Subscript 1 represents copper beads,
subscript 2 represents water. Neglecting any
energy transfer to or from the container.)
Transcribed Image Text:Consider some copper beads that are initially at T, = 200 °C, with each bead having a mass of m, = 1.00 g. Consider also a bucket of water (m, = 1.00 kg) that is initially at T2 = 20.0°C. Suppose you want to raise the temperature of the bucket of water to T, i.e., by dropping N number of copper 1 beads into the water. (Note: Subscript 1 represents copper beads, subscript 2 represents water. Neglecting any energy transfer to or from the container.)
Which is the correct
expression for the (final)
equilibrium temperature T?*
m,c, T, + m2C2T2
T =
m,c1 + m2c2
O A
m,c,T, – m2c2T2
T =
m1C1 + m2C2
O B
m, c,T, + m2c2T2
m1C1 – m2C2
T =
Nm, c, T, + M2C2T2
T =
Nm,c, + m2C2
O D
Nm,c,T, – m2c2T2
T =
Nm,C1 + m2c2
O E
Nm,c,T, + m2czT2
T =
Nmịc - m2c2
O F
None of the above.
Transcribed Image Text:Which is the correct expression for the (final) equilibrium temperature T?* m,c, T, + m2C2T2 T = m,c1 + m2c2 O A m,c,T, – m2c2T2 T = m1C1 + m2C2 O B m, c,T, + m2c2T2 m1C1 – m2C2 T = Nm, c, T, + M2C2T2 T = Nm,c, + m2C2 O D Nm,c,T, – m2c2T2 T = Nm,C1 + m2c2 O E Nm,c,T, + m2czT2 T = Nmịc - m2c2 O F None of the above.
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