Consider the alphabet set Σ = {a b}; Write Regular Expressions for the following definitions. 1. Language of All those words which do not contains double a’s. 2. Language of All those words which do not contains double letters. 3. Language of All those words which has at most three letters.
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Consider the alphabet set Σ = {a b}; Write Regular Expressions for the following
definitions.
1. Language of All those words which do not contains double a’s.
2. Language of All those words which do not contains double letters.
3. Language of All those words which has at most three letters.
4. Language of All those words which do not contains substring ab.
5. Language of All those words in which total number of a’s are divisible by 5
6. Language of All those words which do not contains substring baa.
7. Language of All those words whose length is odd and they contain ab.
8. Language of All those words which ends with bb and have odd length.
9. Language of All those words which do not end with ba.
10. Language of All those words which contains ODD a’s and ODD b’s
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- For each of the languages below, determine whether the language is regular or not. Ifthe language is regular, build a DFA or an NFA that accepts it. If it is not, prove this using the PumpingLemma or the Fooling Set method.(5.a) A language of strings over Σ = {a, b} which contain twice as many symbols b as symbols a.(5.b) L = {uwu |u, w ∈{a, b}∗, |u|= 2}.(5.c) L = {ai#aj #ak |at least two of the numbers i, j, k are equal}.This is the end of the assignment. Good luck!Edsgar Dijkstra is known for his work on programming languages. Hecame up with a neat problem that he called the Dutch National Flagproblem: given a list of strings, each of which is either 'red', 'green', or 'blue'(each is repeated several times in the list), rearrange the list so that thestrings are in the order of the Dutch national flag—all the 'red' stringsfirst, then all the 'green' strings, then all the 'blue' strings.Write a function called dutch_flag that takes a list and solves this problem.Write programs with these input and output Given positive integers m and n, find the number of ontofunctions from a set with m elements to a set with n elements.
- Program in Haskell (Replace the question marks with code). Has to be recursive: my_map :: (a -> b) -> [a] -> [b] my_map = ? my_all :: (a -> Bool) -> [a] -> Bool my_all = ? my_any :: (a -> Bool) -> [a] -> Bool my_any = ? my_filter :: (a -> Bool) -> [a] -> [a] my_filter = ? my_dropWhile :: (a -> Bool) -> [a] -> [a] my_dropWhile = ? my_takeWhile :: (a -> Bool) -> [a] -> [a] my_takeWhile = ? my_break :: (a -> Bool) -> [a] -> ([a], [a]) my_break = ? -- Implement the Prelude functions and, or, concat using foldr my_and :: [Bool] -> Bool my_and = ? my_or :: [Bool] -> Bool my_or = ? my_concat :: [[a]] -> [a] my_concat = ? -- Implement the functions sum, product, reverse using foldl my_sum :: Num a => [a] -> a my_sum = ? my_product :: Num a => [a] -> a my_product = ? my_reverse :: [a] -> [a] my_reverse = ?In Kotlin A. Write a function lengthGreaterThan() with an expression body that takes a String s and an Int n and returns true if the String is at least n characters long. Then revise the function so that it can accept null values. If it receives null as the parameter, it should return false. B. Write a recursive function with an expression body that takes a list of nullable Strings and and Int an returns a list of just the Strings from the original list for which the function you wrote in the first part returns true C. Get the same result as in part B by using filter()The below code is written in C++, can you please write it in Scheme language with comments or explination? thank you!! void antiSymmetric(int b[], int sizeOfB) { bool hold = true; // set hold to true for(int i = 0; i < sizeOfB;) // for each pair (e,f) in b { if(hold == false) { cout << "AntiSymmetric - No" << endl; break; //Did not find (e,e) in b } for(int j = 0; j < sizeOfB;) { if(b[i] == b[j+1] && b[i+1] == b[j]) //If true, then pair(f,e) exists { if(b[i+1] != b[i]) //If true, relation is antisymmetric { hold = true; break; } else { hold = false; j = j + 2; } } else { hold = false; j = j + 2; } } i = i + 2;
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- def reverse_sentence(s: str) -> str:"""Given a sentence <s>, we define a word within <s> to be a continuoussequence of characters in <s> that starts with a capital letter andends before the next capital letter in the string or at the end ofthe string, whichever comes first. A word can include a mixture ofpunctuation and spaces.This means that in the string 'ATest string!', there are in fact only twowords: 'A' and 'Test string!'. Again, keep in mind that words start with acapital letter and continue until the next capital letter or the end of thestring, which is why we consider 'Test string!' as one word.This function will reverse each word found in the string, and return a newstring with the reversed words, as illustrated in the doctest below.>>> reverse_sentence('ATest string!')'A!gnirts tseT' """ do it on python, and do not use any list, import or split, or append or join.def reverse_sentence(s: str) -> str:"""Given a sentence <s>, we define a word within <s> to be a continuoussequence of characters in <s> that starts with a capital letter andends before the next capital letter in the string or at the end ofthe string, whichever comes first. A word can include a mixture ofpunctuation and spaces.This means that in the string 'ATest string!', there are in fact only twowords: 'A' and 'Test string!'. Again, keep in mind that words start with acapital letter and continue until the next capital letter or the end of thestring, which is why we consider 'Test string!' as one word.This function will reverse each word found in the string, and return a newstring with the reversed words, as illustrated in the doctest below.>>> reverse_sentence('watchNow')'watchwoN' >>> reverse_sentence('hot')'hot' """ do it on python, and do not use any list, import or split, or append or join.def reverse_sentence(s: str) -> str:"""Given a sentence <s>, we define a word within <s> to be a continuoussequence of characters in <s> that starts with a capital letter andends before the next capital letter in the string or at the end ofthe string, whichever comes first. A word can include a mixture ofpunctuation and spaces.This means that in the string 'ATest string!', there are in fact only twowords: 'A' and 'Test string!'. Again, keep in mind that words start with acapital letter and continue until the next capital letter or the end of thestring, which is why we consider 'Test string!' as one word.This function will reverse each word found in the string, and return a newstring with the reversed words, as illustrated in the doctest below.>>> reverse_sentence('ATest string!')'A!gnirts tseT'""" pass