12. Consider the recursive function (from class) int gcd( int a, int b) int gcd( int a, int b){ if (b > a) return gcd(b,a); if ( b == 0 ) return a; return gcd( b, a% b); } How many invocation (calls) of the gcd() function will be made by the call gcd(72, 30) ?

In c++ please help me answer this question I will give you a good rating :) implement the three versions of the addupto20() function: iterative, recursive, and divide-and-conquer approach test these functions with a few inputs from your main() Iterative solution * check if there exsits two numbers from vector data that add up to 20 e.g., if data=[2,5,3,15], the function returns true, as data [0] +data [3]==20 e.g., if data=[3,4,0,8], the function return false precondition: vector data has been initialized postcondition: if there are two numbers from list add up to 20, return true; otherwise, return false */ bool AddupTo20 (const vector‹int> & data){ } Come up with a recursive solution to the problem, following the hints given below: * check if there exsits two numbers from vector data[first...right] add up to 20 e.g., if data=[2,5,3,15], first=0, last=3, the function returns true, as data [0] +data [3]==20 e.g., if data=[2,5,3,15], first=2, last=3, the function returns…

In C++ Consider the following recursive function (Chapter 17, #9, modified)   void recFun(int x) {       if (x > 10)       {            recFun(x / 10);            cout<< x % 10;       }       else            cout<< x; }   How can the code be modified so that the sum of all digits is printed?

Give a recursive definition for the set of all strings of a’s and b’s that begins with an a and ends in a b. Say, S = { ab, aab, abb, aaab, aabb, abbb, abab..} Let S be the set of all strings of a’s and b’s that begins with a and ends in a b. The recursive definition is as follows – Base:... Recursion: If u ∈ S, then... Restriction: There are no elements of S other than those obtained from the base and recursion of S.

4. Given the following recursive definitionseq(1) = seq(2) = 1seq(n) = 2 ∗ seq(n − 1) + 3 ∗ seq(n − 2)implement the corresponding program and use it to calculate seq(5).How many invocations are made to the function seq when calculating seq(5)?

In C++: Explain and show how to use the recursive function int gcd (inta, int b).

DO NOT COPY ANSWER FROM ANOTHER QUESTION LEAVE IF you cannot do it perfectly. Otherwise, I will not only DOWN the vote but also REPORT you to the official Chegg team.I won't stop calling Chegg until they really pay attention to this trash behavior. Write a structurally recursive function (prefix->postfix exp) that takes as input an expression in the same little language as Problem 4. prefix->postfix returns an expression of the same form as its input, except that all function applications have been reversed. Finish this Racket code below to answer the question above.(define prefix->postfix(lambda (exp)))

‘Write a function nesting(), which takes an arbitrary number of parameters, and returns a list containing the arguments. Write another function unnesting(), which takes a list L as the parameter and retums a 1D list. Notice that, you should be able to use loops to solve thisproblem and should not use recursive functions (which we will not cover in this course). ‘Write assertions to test the two functions.For example nesting(1, nesting(2, 3, nesting(4, 5, [6])), [7, 8], 9)unnesting([1, [2, 3, [4, 5, [6]]], [7. 8], 9])   (1, [2, 3, [4, 5, [6]]], [7, 8], 9][1, 2,3, 4, 5, 6, 7, 8 9]

Write a recursive Racket function "update-if" that takes two functions, f and g, and a list xs as parameters and evaluates to a list. f will be a function that takes one parameter and evaluates true or false. g will be a function that takes one parameter and evaluates to some output. The result of update-if should be a list of items such that if x is in xs and (f x) is true, then (g x) is in the list. The output list's elements should keep the input list's items in the same relative order. For example (update-if even? add1 '(1 2 3 4)) should evaluate to '(3 5) because 2 and 4 make even? true and add1 turns 2 and 4 into 3 and 5.

program in C++ with the name, towers.cpp which helps to solve the Towers of Hanoi puzzle using this recursive approach. The main() routine should make a single call to the recursive member function do Towers(). This function then calls itself recursively until the puzzle is solved. Note: solve as soon as possible