Consider the below code: public class Test{ LinkedList list = new LinkedList ( ) ; list.add (1); Integer x = list.get (1); What is the value of x? Exception Thrown
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- Would a LinkedList or an ArrayList perform better when run on the following code? Why? public static int min(List<Integer> list) { int min = list.get(0); for (int i = 1; i < list.size(); i++) { if (list.get(i) < min) { min = list.get(i); } } return min; }I need to add an item to a linked list using a method. its an object consisting of a name, int, double, double, int. public static Person addPerson (Person head, Person toAdd, int position) { }Java Given main() in the Inventory class, define an insertAtFront() method in the InventoryNode class that inserts items at the front of a linked list (after the dummy head node).
- Java Given main() in the ShoppingList class, define an insertAtEnd() method in the ItemNode class that adds an element to the end of a linked list. DO NOT print the dummy head node. Ex. if the input is: 4 Kale Lettuce Carrots Peanuts where 4 is the number of items to be inserted; Kale, Lettuce, Carrots, Peanuts are the names of the items to be added at the end of the list. The output is: Kale Lettuce Carrots Peanuts Second image is ItemNodeGiven two linked lists sorted in increasing order, write a method intersection( ) to return a new list representing the intersection of the two lists. The new list should be made with its own memory — the original lists should not be changed. Example: if list1 contains {3,4,7,9,11} and list contains {2,3,8,9,12,15} so the intersection list3 is {3,9}.Given main() in the ShoppingList class, define an insertAtEnd() method in the ItemNode class that adds an element to the end of a linked list. DO NOT print the dummy head node. Ex. if the input is: 4 Kale Lettuce Carrots Peanuts where 4 is the number of items to be inserted; Kale, Lettuce, Carrots, Peanuts are the names of the items to be added at the end of the list. The output is: Kale Lettuce Carrots Peanuts public class ItemNode { private String item; private ItemNode nextNodeRef; // Reference to the next node public ItemNode() { item = ""; nextNodeRef = null; } // Constructor public ItemNode(String itemInit) { this.item = itemInit; this.nextNodeRef = null; } // Constructor public ItemNode(String itemInit, ItemNode nextLoc) {…
- Trying this again since part of my question keeps disappearing Given main() in the ShoppingList class, define an insertAtEnd() method in the ItemNode class that adds an element to the end of a linked list. DO NOT print the dummy head node. Ex. if the input is: 4 Kale Lettuce Carrots Peanuts where 4 is the number of items to be inserted; Kale, Lettuce, Carrots, Peanuts are the names of the items to be added at the end of the list. The output is: Kale Lettuce Carrots Peanuts public class ItemNode { private String item; private ItemNode nextNodeRef; // Reference to the next node public ItemNode() { item = ""; nextNodeRef = null; } // Constructor public ItemNode(String itemInit) { this.item = itemInit; this.nextNodeRef = null; } // Constructor…Sometimes a number is the same when you read it from front to back and from back to front. Write a Method Called makePalindrome() that will return a linked list with a palindrome of the calling list (generic linked list). The calling list and the palindrome list must be returned as one list. Write a test programme that tests all special cases for the linked listHow to get insert method to accept two values? Right now it accepts one, and ignores the other. class Node: """ Represents a node in a linked list """ def __init__(self, data): self.data = data self.next = None class LinkedList: """ A linked list implementation of the List ADT """ def __init__(self): self._head = None def add(self, val): """ Adds a node containing val to the linked list """ self._head = self.rec_add(self._head, val) def rec_add(self, a_node, val): """ Adds a node containing val to the linked list """ if a_node is None: return Node(val) else: a_node.next = self.rec_add(a_node.next, val) return a_node def insert(self, val, pos): """ Adds a node containing val to the linked list """ self._head = self.insert_add(self._head, val, pos) def insert_add(self, a_node, val, pos): """…
- Create code that will find duplicate keys in a linked list and remove them all.Given the MileageTrackerNode class, complete main() in the MileageTrackerLinkedList class to insert nodes into a linked list (using the insertAfter() method). The first user-input value is the number of nodes in the linked list. Use the printNodeData() method to print the entire linked list. DO NOT print the dummy head node. Ex. If the input is: 3 2.2 7/2/18 3.2 7/7/18 4.5 7/16/18 the output is: 2.2, 7/2/18 3.2, 7/7/18 4.5, 7/16/18 public class MileageTrackerNode { private double miles; // Node data private String date; // Node data private MileageTrackerNode nextNodeRef; // Reference to the next node public MileageTrackerNode() { miles = 0.0; date = ""; nextNodeRef = null; } // Constructor public MileageTrackerNode(double milesInit, String dateInit) { this.miles =…1- A new static method with one parameter which is a head node for a linked list of integers, the method should create a new linked list which is equivalent to the original list of integers but with all repetitions removed, the method's return value is a head reference for the new list. this is what I have but it's not removing repetitions. public static IntLinkedBag removeRepetition (IntLinkedBag b1) { IntNode next; IntNode head = null; LinkedList<Integer> s = new LinkedList<>(); IntNode new_list = new IntNode(0, null); IntNode now = head; IntNode prev = new_list; while (now!= null) { int x = now.data; if (s.contains(x)) { new_list = new_list.next; } else { s.add(x); new_list.next = new IntNode(x, now); new_list = new_list.next; } now = now.next; } return b1; } }…
