Consider the combustion of butane: 2C4​H10​(g)+13O2​(g)-->8CO2​(g)+10H2​O(l), ΔHrxn = −2878 kJ/mol How much heat will be released if 425 mL of butane gas at 45°C and 792 mmHg is burned in the reaction above?

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Chapter2: The First Law Of Thermodynamics
Section: Chapter Questions
Problem 2.79E: The enthalpy of combustion of diamond is -395.4 kJ/mol. C s, dia O2 g CO2 g Determine the fH of C...
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Consider the combustion of butane:

2C4​H10​(g)+13O2​(g)-->8CO2​(g)+10H2​O(l), ΔHrxn = −2878 kJ/mol

How much heat will be released if 425 mL of butane gas at 45°C and 792 mmHg is burned in the reaction above?

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For the combustion of butane:

2C4​H10​(g)+13O2​(g)-->8CO2​(g)+10H2​O(l), ΔHrxn = −2878 kJ/mol

Volume of butane, V=425 mL =425 /1000=0.425 L

Temperature, T= 45°C =45 + 273=318 K

Pressure, P=792 mmHg =792 / 760 atm

Number of moles, n =?

Heat released=?

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