Consider the conducting loop from problem 5 of problem set 11 also shown below. It is a square loop of side length, L, that now rotates about the x axis at constant angular velocity such that 0 = wt. Ignore the I labeled on the diagram for this problem there is a current, but it's not constant. a. Show by explicit calculation that the emf generated in the loop as the loop rotates is given by Faraday's law: dºM dt

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Chapter1: Introduction
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Side view
i out of page
L.
1111
By this, I mean: consider a charge q in the conductor, evaluate the magnetic force that acts
on the charge along different parts of the loop. Then directly evaluate the EMF,
1
E =
Note: only two sides of the loop contribute, though you should show that.
b. Obtain an expression for the emf as a function of time. Such an EMF would be considered
an “AC" power source.
Transcribed Image Text:Side view i out of page L. 1111 By this, I mean: consider a charge q in the conductor, evaluate the magnetic force that acts on the charge along different parts of the loop. Then directly evaluate the EMF, 1 E = Note: only two sides of the loop contribute, though you should show that. b. Obtain an expression for the emf as a function of time. Such an EMF would be considered an “AC" power source.
Consider the conducting loop from problem 5 of problem set 11 also shown below. It is a square
loop of side length, L, that now rotates about the x axis at constant angular velocity such that
0 = wt. Ignore the I labeled on the diagram for this problem – there is a current, but it's not
constant.
a. Show by explicit calculation that the emf generated in the loop as the loop rotates is given
by Faraday's law:
dºM
E =
dt
Transcribed Image Text:Consider the conducting loop from problem 5 of problem set 11 also shown below. It is a square loop of side length, L, that now rotates about the x axis at constant angular velocity such that 0 = wt. Ignore the I labeled on the diagram for this problem – there is a current, but it's not constant. a. Show by explicit calculation that the emf generated in the loop as the loop rotates is given by Faraday's law: dºM E = dt
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