Consider the curve segments: 1 S1: y = x from x =to x = 4 and S2: y = Va from x = - to x = 16. Set up integrals that give the arc lengths of the curve segments by integrating with respect to y. 16 The length of the first segment is Lj = + 2ydy and the length of the second segment is L2 = -dy. + 2y 16 1 The length of the first segment is Lj = + -dy and the length of the second segment is L2 = / V1+ 4y² dy. 4y 16 The length of the first segment is Lj = + 4y dy and the length of the second segment is L2 = | V!+4y²dy. 1+4y° dy and the length of the second segment is L2 = dy. 2y The length of the first segment is Lj = 16 The length of the first segment is Lj = / VI + 2ydy and the length of the second segment is L2 = -dy. 2y -ler

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