Consider the DE d'y + 16- + 64y = I dz2 dr hich is linear with constant coefficients. irst we will work on solving the corresponding homogeneous equation. The auxiliary equation (using m as your variable) is = 0 which has root Because this is a repeated root, we don't have much choice but to use the exponential function corresponding to this root to do reduction of order. 8z 2 = ue Then (using the prime notation for the derivatives) So, plugging Y2 into the left side of the differential equation, and reducing, we get

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Consider the DE
d'y
fip
+ 16-
+ 64y = I
dz2
da
which is linear with constant coefficients.
First we will work on solving the corresponding homogeneous equation. The auxiliary equation (using m as your variable) is
O which has root
Because this is a repeated root, we don't have much choice but to use the exponential function corresponding to this root
to do reduction of order.
Y2 = ue
Then (using the prime notation for the derivatives)
So, plugging Y2 into the left side of the differential equation, and reducing, we get
y + 16y, + 64y2 =
So now our equation is e 8Iu" = r. To solve for u we need only integrate re twice, using a as our first constant of integration and b as the
second we get
Therefore y2
the general solution.
Transcribed Image Text:Consider the DE d'y fip + 16- + 64y = I dz2 da which is linear with constant coefficients. First we will work on solving the corresponding homogeneous equation. The auxiliary equation (using m as your variable) is O which has root Because this is a repeated root, we don't have much choice but to use the exponential function corresponding to this root to do reduction of order. Y2 = ue Then (using the prime notation for the derivatives) So, plugging Y2 into the left side of the differential equation, and reducing, we get y + 16y, + 64y2 = So now our equation is e 8Iu" = r. To solve for u we need only integrate re twice, using a as our first constant of integration and b as the second we get Therefore y2 the general solution.
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