Consider the equilibrium system described by the chemical reaction below. At equilibrium, a 2.0 L reaction vessel contained a mixture of 1.2 mol Fe, 1.0 × 10-³ mol O₂, and 2.0 mol of Fe₂O, at 2000.0 °C. What are the values of Kc and Kp for this reaction? 4Fe(s) + 30₂(g) = 2Fe₂O₂(s) NEXT Based on the given data, set up the expression for Kc. Each reaction participant must be represented by one tile. Do not combine terms. [1.2] Once the expression is constructed, solve for Kc. Complete Parts 1-2 before submitting your answer. 2[2.0] 2[1.2] [1.0 × 10³] [0.50] 8.0 × 10⁰ Кс 1 = [2.0] [5.0 x 10²] 1.0 × 10⁹ [1.2]¹ [0.50]* 1.3 x 10-1⁰ [1.0 × 10.³1³ [5.0 × 10.¹1³ 2 = [2.0]² [1.2]² 4[1.2] 4[0.50] > RESET 3[1.0 × 10³] 3[5.0 x 10+]

Chemistry: The Molecular Science
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Author:John W. Moore, Conrad L. Stanitski
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Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 61QRT
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Consider the equilibrium system described by the chemical reaction below. At
equilibrium, a 2.0 L reaction vessel contained a mixture of 1.2 mol Fe, 1.0 × 10.³
mol O₂, and 2.0 mol of Fe₂O at 2000.0 °C. What are the values of Kc and Kp for
this reaction?
2⁹
2
3
[1.2]
2[2.0]
Based on the given data, set up the expression for Kc. Each reaction participant must be
represented by one tile. Do not combine terms.
2[1.2]
Once the expression is constructed, solve for Kc. Complete Parts 1-2 before submitting your
answer.
[1.0 × 10³]
[0.50]
1
8.0 × 10⁹
Kc =
4Fe(s) + 30₂(g) = 2Fe₂O₂(s)
[2.0]
[5.0 × 10²]
1.0 × 10⁹
[1.2]¹
[0.50]*
1.3 × 10-1⁰
[1.0 × 10-³]³
2
[5.0 × 10-41³
||
[2.0]²
[1.2]²
NEXT
4[1.2]
4[0.50]
>
RESET
3[1.0 × 10.³]
3[5.0 × 104]
Transcribed Image Text:Consider the equilibrium system described by the chemical reaction below. At equilibrium, a 2.0 L reaction vessel contained a mixture of 1.2 mol Fe, 1.0 × 10.³ mol O₂, and 2.0 mol of Fe₂O at 2000.0 °C. What are the values of Kc and Kp for this reaction? 2⁹ 2 3 [1.2] 2[2.0] Based on the given data, set up the expression for Kc. Each reaction participant must be represented by one tile. Do not combine terms. 2[1.2] Once the expression is constructed, solve for Kc. Complete Parts 1-2 before submitting your answer. [1.0 × 10³] [0.50] 1 8.0 × 10⁹ Kc = 4Fe(s) + 30₂(g) = 2Fe₂O₂(s) [2.0] [5.0 × 10²] 1.0 × 10⁹ [1.2]¹ [0.50]* 1.3 × 10-1⁰ [1.0 × 10-³]³ 2 [5.0 × 10-41³ || [2.0]² [1.2]² NEXT 4[1.2] 4[0.50] > RESET 3[1.0 × 10.³] 3[5.0 × 104]
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