Consider the figure and the partially completed paragraph proof. b a Q e f R C Since the three triangles are similar, the ratio of the lengths of the corresponding sides of the largest and smallest = = , and the ratios of the lengths of the corresponding sides of the largest and second . Using the Cross Products Property, these can be rewritten as a? = ce and . Then, by using substitution, a +b = ce + cf. By factoring, a +b² = c(e+ f). Next, by looking at the triangles can be written as largest triangles can be written as original triangle, (e+ f) = c. Lastly, by using substitution, a2 + 6? = c(c) = c². P

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
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Chapter6: Ratio, Proportion, And Probability
Section: Chapter Questions
Problem 4CST
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Since the three triangles are similar, the ratio of the lengths of the corresponding sides of the largest and smallest triangles can be written as a/c = e/a, and the ratios of the lengths of the corresponding sides of the largest and second largest triangles can be written as ______. Using the Cross Products Property, these can rewritten as a2= ce and _______. Then, by using substitution, a2 + b2=ce + cf. By factoring, a2 + b2= c (e+f). Next, by looking at the original triangle, (e+f) =c. Lastly, by using substitution, a2+b2=c (c)=c2.
Consider the figure and the partially completed paragraph proof.
b
a
Q
e
R
C
Since the three triangles are similar, the ratio of the lengths of the corresponding sides of the largest and smallest
E, and the ratios of the lengths of the corresponding sides of the largest and second
Using the Cross Products Property, these can be rewritten as a? = ce and
ce + cf. By factoring, a? + b² =c(e+f). Next, by looking at the
triangles can be written as
largest triangles can be written as
Then, by.using substitution, a² + b2 :
original triangle, (e+ f) = c. Lastly, by using substitution, a² + b? = c(c) = c².
||
Transcribed Image Text:Consider the figure and the partially completed paragraph proof. b a Q e R C Since the three triangles are similar, the ratio of the lengths of the corresponding sides of the largest and smallest E, and the ratios of the lengths of the corresponding sides of the largest and second Using the Cross Products Property, these can be rewritten as a? = ce and ce + cf. By factoring, a? + b² =c(e+f). Next, by looking at the triangles can be written as largest triangles can be written as Then, by.using substitution, a² + b2 : original triangle, (e+ f) = c. Lastly, by using substitution, a² + b? = c(c) = c². ||
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