6.PracticeCRM 2.1 - Lesson 14Consider the figure below.MABCGiven: mLA = mzD, AP = DQ, AB = BC = CDProve: BM = CMa. Complete the following two-column proof.StatementsReasons1. mLA = mzD1. Given2. AP = DQ, AB = BC = CD2. Given3.3. Segment Addition Postulate4. AB + BC = DB4.5.5. Transitive Property6. A CAP =A BDQ6.7.7. СРСТС8. BM = CM8.b.Prove BM = CM by applying properties oftransformations. Justify your steps.

Given: m∠A=m∠D, AP¯≅DQ¯, AB¯≅BC¯≅CD¯

Consider the figure below. P M A B Given: mLA = mLD, AP = DQ, AB = BC = CD Prove: BM = CM a. Complete the following two-column proof. Statements Reasons 1. mLA = m2D 1. Given 2. AP = DQ, AB = BC = CD 2. Given 3. 3. Segment Addition Postulate 4. AB + BC = DB 4. 5. 5. Transitive Property 6. △ CAP 열스 BDQ 6. 7. |7. СРСТС 8. BM = CM 8. b. Prove BM = CM by applying properties of transformations. Justify your steps.