Consider the following definition of a MysteryBox object: public class MysteryBox { private final int x0, x1, x2, x3; private final double y0; private final boolean z0; private final long[] a = new long [248]; ... } Using the 64-bit memory cost model from lecture, how many bytes does each object of type MysteryBox consume? Include all memory referenced by the object (deep memory Answer Your answer should be a positive integer that is a multiple of 8.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
Consider the following definition of a MysteryBox object:
public class MysteryBox {
private final int x0, x1, x2, x3;
private final double y0;
private final boolean z0;
private final long[] a = new long [248];
}
Using the 64-bit memory cost model from lecture, how many bytes does each object
of type MysteryBox consume? Include all memory referenced by the object (deep memory).
Answer
Your answer should be a positive integer that is a multiple of 8.
Transcribed Image Text:Question Consider the following definition of a MysteryBox object: public class MysteryBox { private final int x0, x1, x2, x3; private final double y0; private final boolean z0; private final long[] a = new long [248]; } Using the 64-bit memory cost model from lecture, how many bytes does each object of type MysteryBox consume? Include all memory referenced by the object (deep memory). Answer Your answer should be a positive integer that is a multiple of 8.
Question
What is the order of growth of the worst-case running time of
the following code fragment as a function of n?
int sum = 0;
for (int i
for (int j
1; i <= n; i++)
1; j
i*i; j++)
く=
sum++;
Answer
Mark the best answer.
01
'log n
On^(1/2)
n log n
On^(3/2)
n^2
n^2 log n
n^(5/2)
On^3
On^4
n^5
On^6
On^7
Transcribed Image Text:Question What is the order of growth of the worst-case running time of the following code fragment as a function of n? int sum = 0; for (int i for (int j 1; i <= n; i++) 1; j i*i; j++) く= sum++; Answer Mark the best answer. 01 'log n On^(1/2) n log n On^(3/2) n^2 n^2 log n n^(5/2) On^3 On^4 n^5 On^6 On^7
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