Consider the following integral: 50 i cos (10) COS = 10 sin(5)~-9.5892 0 Using an integration step size of 12.5 and the Trapezoidal method, the integral can be found to have an error of 0.582 per step. Approximately how large would you expect the per-step error to be if a step size of 6.25 is used? O a. 0.036 per step O b. 0.018 per step O c. 0.073 per step O d. 0.146 per step

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