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Consider the following reaction: 2 NO (g) N2 (g) + O2 (g), Kc = 4.0 You start the reaction with 10.0 moles of NO in a 2.0 L vessel. Set up the ICE table for this problem and then set up to solve for x (the concentration of N2). You should end up with a quadratic equation. The quadratic equation in the form, (ax2 + bx + c = 0) is: 3.0x2 − 20x + 25 = 0 x2 − 8.0x + 20 = 0 3.0x2 − 40x + 100 = 0 15x2 − 160x + 400 = 0 15x2 − 80x + 100 = 0

Consider the following reaction: 2 NO (g) N2 (g) + O2 (g), Kc = 4.0 You start the reaction with 10.0 moles of NO in a 2.0 L vessel. Set up the ICE table for this problem and then set up to solve for x (the concentration of N2). You should end up with a quadratic equation. The quadratic equation in the form, (ax2 + bx + c = 0) is: 3.0x2 − 20x + 25 = 0 x2 − 8.0x + 20 = 0 3.0x2 − 40x + 100 = 0 15x2 − 160x + 400 = 0 15x2 − 80x + 100 = 0

Chemistry for Engineering Students
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter3: Molecules, Moles, And Chemical Equations
Section: Chapter Questions
Problem 3.67PAE
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Consider the following reaction:

 
2 NO (g)  N2 (g) + O2 (g), Kc = 4.0

 
You start the reaction with 10.0 moles of NO in a 2.0 L vessel. Set up the ICE table for this problem and then set up to solve for x (the concentration of N2). You should end up with a quadratic equation. The quadratic equation in the form, (ax2 + bx + c = 0) is:

   

3.0x2 − 20x + 25 = 0
   

x2 − 8.0x + 20 = 0
   

3.0x2 − 40x + 100 = 0
   

15x2 − 160x + 400 = 0
   

15x2 − 80x + 100 = 0
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