Consider the following reaction between sulfur trioxide and water: SO3(g)+H2O(l)→H2SO4(aq) A chemist allows 61.5 g of SO3 and 11.2 g of H2O to react. When the reaction is finished, the chemist collects 55.3 g of H2SO4 .Determine the limiting reactant for the reaction.Express your answer as a chemical formula.

Question
Asked Oct 8, 2019

Consider the following reaction between sulfur trioxide and water:
SO3(g)+H2O(l)→H2SO4(aq) A chemist allows 61.5 g of SO3 and 11.2 g of H2O to react. When the reaction is finished, the chemist collects 55.3 g of H2SO4 .

Determine the limiting reactant for the reaction.

Express your answer as a chemical formula.
check_circleExpert Solution
Step 1

From the given mass of sulfur trioxide and water...

so, (g)+H20()H,SO.(aq)
61.5g
11.2g
55.3g
mass
moles molar mass
molarmassof SO,-80.066 g/mol
molar massof H2O=18.015 g/mol
moles of SO
61.5g
80.066 g/mol
0.768mol
moles of H2O:
11.2g
18.015 g/mol
0.622mol
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so, (g)+H20()H,SO.(aq) 61.5g 11.2g 55.3g mass moles molar mass molarmassof SO,-80.066 g/mol molar massof H2O=18.015 g/mol moles of SO 61.5g 80.066 g/mol 0.768mol moles of H2O: 11.2g 18.015 g/mol 0.622mol

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